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3 years ago

What is an equation of the line that passes through the points (-3, -5) and (-3, -8)?

Mathematics

2 answers:

Viktor [21]3 years ago

8 0

This is an undefined problem

mart [117]3 years ago

8 0

Answer:

x = -3

Step-by-step explanation:

Hi there!

Typically, linear equations would be organized in slope-intercept form: y=mx+b where m is the slope and b is the y-intercept (the value of y when the line crosses the y-axis).

However, notice how the two x-coordinates of the given points are the same. They're both -3. This means that this is a vertical line, and vertical lines are organized in this equation: x=d where d is the x-intercept (the value of x when the line crosses the x-axis).

We know that the x-intercept is -3, since all the x-coordinates of the points that a vertical line passes through are the same. Therefore, the equation of this line is x=-3.

I hope this helps!

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pogonyaev

The highest common factor of both terms is 4x, so take this out by dividing each term by 4x

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12x / 4x = 3

So the factored form is:
4x(2x+3)

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2 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

Calculate the arithmetic sequence in which a9=17 and the common difference is d=-2.1

jek_recluse [69]

Answer:

$S_{31}=71.3$

Step-by-step explanation:

The nth term of an arithmetic sequence is given by the formula,

$U_n=a_1+(n-1)d$

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$\Rightarrow 17=a_1+(9-1)(-2.1)$

$\Rightarrow 17=a_1+(8)\times(-2.1)$

$\Rightarrow 17=a_1-\frac{84}{5}$

$\Rightarrow 17+\frac{84}{5}=a_1$

$\Rightarrow a_1=\frac{169}{5}$

The sum of the first n-terms is given by the formula,

$S_n=\frac{n}{2}(2a_1+(n-1)d)$

To find $S_{31}$ , we substitute $n=31$ , $a_1=\frac{169}{5}$ and $d=-2.1$ .

$\Rightarrow S_{31}=\frac{31}{2}(2(\frac{169}{5}+(31-1)(-2.1))$

$\Rightarrow S_{31}=\frac{31}{2}(2(\frac{169}{5}+(30)(-2.1))$

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$\Rightarrow S_{31}=\frac{713}{10}$

$\Rightarrow S_{31}=71.3$

The correct answer is D

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Answer:

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2 years ago

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