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enyata [817]
3 years ago
9

• A florist is arranging flowers for a wedding. For every 2 pink flowers in a vase, he also includes 8 white

Mathematics
1 answer:
gregori [183]3 years ago
6 0

Answer: It's 1 - 4

2 -8

3 -12

6 - 24 Your welcome

Step-by-step explanation:

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How can i find the distance of AM.
ozzi

Answer:

AM=5

Step-by-step explanation:

AM=MC

3y-4=2y-1

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3 years ago
Eagle Outfitters is a chain of stores specializing in outdoor apparel and camping gear. They are considering a promotion that in
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Answer:

a) <u>Alternative hypothesis:</u> the use of the coupons is isgnificantly higher than 10%.

<u>Null hypothesis:</u> the use of the coupons is not significantly higher than 10%.

The null and alternative hypothesis can be written as:

H_0: \pi=0.1\\\\H_a:\pi>0.1

b) Point estimate p=0.13

c) At a significance level of 0.05, there is not enough evidence to support the claim that the proportion of coupons use is significantly higher than 10%.

Eagle should not go national with the  promotion as there is no evidence it has been succesful.

Step-by-step explanation:

<em>The question is incomplete.</em>

<em>The sample data shows that x=13 out of n=100 use the coupons.</em>

This is a hypothesis test for a proportion.

The claim is that the proportion of coupons use is significantly higher than 10%.

Then, the null and alternative hypothesis are:

H_0: \pi=0.1\\\\H_a:\pi>0.1

The significance level is 0.05.

The sample has a size n=100.

The point estimate for the population proportion is the sample proportion and has a value of p=0.13.

p=X/n=13/100=0.13

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.1*0.9}{100}}\\\\\\ \sigma_p=\sqrt{0.0009}=0.03

Then, we can calculate the z-statistic as:

z=\dfrac{p-\pi-0.5/n}{\sigma_p}=\dfrac{0.13-0.1-0.5/100}{0.03}=\dfrac{0.025}{0.03}=0.833

This test is a right-tailed test, so the P-value for this test is calculated as:

\text{P-value}=P(z>0.833)=0.202

As the P-value (0.202) is greater than the significance level (0.05), the effect is  not significant.

The null hypothesis failed to be rejected.

At a significance level of 0.05, there is not enough evidence to support the claim that the proportion of coupons use is significantly higher than 10%.

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3 years ago
Is ( 1,-1) a solution to the following system of inequalities:
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