Answer:
This is always ''interesting'' If you see an absolute value, you always need to deal with when it is zero:
(x-4)=0 ===> x=4,
so that now you have to plot 2 functions!
For x<= 4: what's inside the absolute value (x-4) is negative, right?, then let's make it +, by multiplying by -1:
|x-4| = -(x-4)=4-x
Then:
for x<=4, y = -x+4-7 = -x-3
for x=>4, (x-4) is positive, so no changes:
y= x-4-7 = x-11,
Now plot both lines. Pick up some x that are 4 or less, for y = -x-3, and some points that are 4 or greater, for y=x-11
In fact, only two points are necessary to draw a line, right? So if you want to go full speed, choose:
x=4 and x= 3 for y=-x-3
And just x=5 for y=x-11
The reason is that the absolute value is continuous, so x=4 works for both:
x=4===> y=-4-3 = -7
x==4 ====> y = 4-11=-7!
abs() usually have a cusp int he point where it is =0
Step-by-step explanation:
7.28 is the answer sorry if i’m wrong
Answer:
What's the question?
Step-by-step explanation:
First Blank : Linear
Second Blank: One solution
Third Blank: Infinite solutions
Fourth Blank: (i don't know) but i am thinking that it is a single point which marks the intersection of the two (or more) graphed lines. its like the point of intersection
10C9 * (1/5)^9 * (4/5)^1 = 4.096*10^-6
About 4 chances in 1 million.
