Answer:
B. Box B
Step-by-step explanation:
Which ever box's volume is the largest, that box would cost the most.
The <u>volume of a rectangular box is length * width * height</u>
Let's find the volumes of each of the boxes:
1. Box A Volume = 10.5 * 12 * 4.5 = 567 cu. in.
2. Box B Volume = 8.5 * 8.5 * 8.5 = 614.125 cu. in.
3. Box C Volume = 10.5 * 8.5 * 6.5 = 580.125 cu. in.
4. Box D Volume = 12 * 6.5 * 6.5 = 507 cu. in.
We can clearly see that Box B has the largest volume. Hence, <em><u>Box B is the most expensive to ship. </u></em>
140 degrees, because the sum of the angles of an isosceles triangle equals to 180 degrees.
Explanation: So if the 2 base angles have a sum of 50 then the third angle is 180-50=130
I would go with A... But im not quite sure :) Good luck
-60x^3 + 480, that’s what I got
The answer is
![- \frac{1}{10}](https://tex.z-dn.net/?f=-%20%5Cfrac%7B1%7D%7B10%7D%20)
To figure this out, convert both numbers to fractions. 1.03 = 1
![\frac{3}{100}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B100%7D%20)
and (-10.3) = -10
![\frac{3}{10}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B10%7D%20)
. Now, convert to improper fractions.
1
![\frac{3}{100} = [tex] \frac{103}{100}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B100%7D%20%20%3D%20%5Btex%5D%20%5Cfrac%7B103%7D%7B100%7D%20)
-10
![\frac{3}{10}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B10%7D%20)
=
![- \frac{103}{10}](https://tex.z-dn.net/?f=-%20%5Cfrac%7B103%7D%7B10%7D%20)
Now, divide. Dividing fractions is the same as multiplying by the reciporical. So:
![-\frac{103}{10} \ becomes\ \frac{10}{103}](https://tex.z-dn.net/?f=%20-%5Cfrac%7B103%7D%7B10%7D%20%20%5C%20becomes%5C%20%20%5Cfrac%7B10%7D%7B103%7D%20)