Th three numbers he could of had on his uniform are 60 30 or 90
Answer: The vector relies on how the objects of where the magnitude and directions should lay on.
Step-by-step explanation:
So, I’ll help you with these 4 problems. So, for the vector 2/4, it would 2 units up and 4 units to the right. The second would be 5 units down and 6 units to the right. The third one would be 3 units up and 1 unit to the left. The last one would be 10 units downs and 12 units to the left. A simplified way of thinking of this is to just look at the signs of the number and see where the vector’s magnitude and directions would go in that point of view when you visual the graph or count it in your head.
Option A:
V = 1/3 * b^2 * h
V = 1/3 * 10.5^2 * 6
V = 1/3 * 110.25 * 6
V = 220.5
Option B:
V = 1/3 * b^2 * h
V = 1/3 * 3.6^2 * 8
V = 1/3 * 12.96 * 8
V = 34.56
Option C:
V = 1/3 * b^2 * h
V = 1/3 * 4.2^2 * 12
V = 1/3 * 17.64 * 12
V = 70.56
Option D:
V = 1/3 * b^2 * h
V = 1/3 * 6^2 * 8.4
V = 1/3 * 36 * 8.4
V = 100.8
I guess it's 'None of the Above'
19: He multiplied instead of dividing which will make a totally incorrect answer
The answer is -4 hope that helps :)
