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hichkok12 [17]
2 years ago
13

16.872 divided by 0.24 HELP I NEED HELP QUICJ

Mathematics
2 answers:
goldenfox [79]2 years ago
6 0

Answer:

70.3

Step-by-step explanation:

16.872/.24= 70.3

ruslelena [56]2 years ago
3 0

Answer: = 70.3

Step-by-step explanation:

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Which expression can be used to approximate the expression below,for all positive number a,b and x where a =/ 1 and b=/ 1
rodikova [14]

Answer:

The correct option is 1.

Step-by-step explanation:

The given expression is

log_ax

The value of a is 1 and the value of b is 1.

According to the logarithm property,

log_mn=\frac{log_pm}{log_pn}

Using this property, we get

log_ax=\frac{log_bx}{log_ba}

The required expression is \frac{log_bx}{log_ba}.

log_1x=\frac{log_1x}{log_11}

log_1x=log_1x                   [\because log_aa=1]

Left hand side is equal to the right hand sides, therefore option 1 is correct.

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7 0
3 years ago
Solve for x: 2|x − 3| + 1 = 7
bearhunter [10]
***SOLVE FOR X***


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6 0
3 years ago
Convert from rectangular to polar coordinates:Note: Choose r and θ such that r is non-negative and 0 ≤ θ &lt; 2πa. (6,0)b. (9,9/
Anuta_ua [19.1K]

Answer:

The polar coordinates are as follow:

a. (6,2π)

b. (18, π/3)

c. (2√2 , 3π/4)

d. (2, 5π /6)

Step-by-step explanation:

To convert the rectangular coordinates into polar coordinates, we need to calculate r, θ .

To calculate r, we use Pythagorean theorem:

r = \sqrt{ x^{2} +y^{2} } ---- (1)

To calculate the θ, first we will find out the θ '  using the inverse of cosine as it is easy to calculate.

So,    θ '  = cos ⁻¹  (x/r)

If  y  ≥  0  then  θ  =  ∅

If  y  <  0  then  θ  =  2 π  −  ∅

For a. (6,0)

Sol:

Using the formula in equation (1). we get the value of r as:

r = \sqrt{6^{2} + 0^{2}  }

r = 6

And ∅  = cos ⁻¹  (x/r)

∅ = cos ⁻¹  (6/6)

∅  =cos ⁻¹   (1) = 2π

As If  y  ≥  0  then  θ  =  ∅

So ∅ = 2π

The polar coordinates are (6,2π)

For a. (9,9/\sqrt{3})

Sol:

r = 9 + 3(3) = 18

and ∅  = cos ⁻¹  (x/r)

∅ = cos ⁻¹  (9/18)

∅ = cos ⁻¹   (1/2) = π/3

As  If  y  ≥  0  then  θ  =  ∅

then θ  = π/3

The polar coordinates are (18, π/3)

For (-2,2)

Sol:

r =√( (-2)²+(2)² )

r = 2 √2

and ∅  = cos ⁻¹  (x/r)

∅ = cos ⁻¹  (-2/ 2 √2)

∅ = 3π/4

As  If  y  ≥  0  then  θ  =  ∅

then   θ  = 3π/4

The polar coordinates are (2√2 , 3π/4)

For (-√3, 1)

Sol:

r = √ ((-√3)² + 1²)

r = 2

and ∅  = cos ⁻¹  (x/r)

∅  = cos ⁻¹ ( -√3/2)

∅  = 5π /6

As  If  y  ≥  0  then  θ  =  ∅

So  θ  = 5π /6

The polar coordinates are (2, 5π /6)

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2 years ago
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