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Sedbober [7]
3 years ago
5

Three teams, A, B and C, play in a competition.

Mathematics
1 answer:
Snezhnost [94]3 years ago
3 0

Answer:

42 games

Step-by-step explanation:

From the ratio, we can deduce that;

For every 3 games A won, B won 1

Thus, if B won 10, then A has won 3(10) = 30

From the second part;

For every 1 game won by C, B won 5

since B won 10, then C won 10/5 = 2

So the total number of games won is;

A + B + C

= 2 + 30 + 10 = 42 games

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