Answer:
Step-by-step explanation:
Given the following system of equations:
In order to solve the system of equations using the Elimination Method, you can follow these steps:
- Multiply the first equation by -6 and the secondd equation by 4.
- Add both equations.
- Solve for "y".
Then:
- Substitute the value of "y" into one of the original equations and solve for "x":
Answer:
The point will come in III quadrant
Step-by-step explanation:
The graph is as follows:
Consider the equation y = x^2. No matter what x happens to be, the result y will never be negative even if x is negative. Example: x = -3 leads to y = x^2 = (-3)^2 = 9 which is positive.
Since y is never negative, this means the inverse x = sqrt(y) has the right hand side never be negative. The entire curve of sqrt(x) is above the x axis except for the x intercept of course. Put another way, we cannot plug in a negative input into the square root function for this reason. This similar idea applies to any even index such as fourth roots or sixth roots.
Meanwhile, odd roots such as a cube root has its range extend from negative infinity to positive infinity. Why? Because y = x^3 can have a negative output. Going back to x = -3 we get y = x^3 = (-3)^3 = -27. So we can plug a negative value into the cube root to get some negative output. We can get any output we want, negative or positive. So the range of any radical with an odd index is effectively the set of all real numbers. Visually this produces graphs that have parts on both sides of the x axis.
Because we know the midpoint is in the middle, we know that both sides are equal.
So set both = to each other
4x - 1 = 3x + 3
add 1 to both sides
4x=3x+4
then subtract 3x from both sides and because there is always a 1 in front of x the answer would be
x=4
