All categories

2 years ago

Nine cyclists were each asked the distance in miles they biked last week.

Mathematics

1 answer:

Ivahew [28]2 years ago

4 0

Answer:

Its A or the first option

Step-by-step explanation:

good luck

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Round $8.0443 to the nearest cent

Lapatulllka [165]

$8.04 because the four is rounding down, therefore it should be $8.04.

I hope this helps.

8 0

2 years ago

The midpoint between y and 33 is -7. Find y

Basile [38]

Answer:

y = -47

Step-by-step explanation:

To find the midpoint of two points, add them together and divide by 2

(y+33)/2 = -7

To find y, multiply each side by 2

(y+33)/2 *2 = -7*2

y+33 = -14

Subtract 33 from each side

y+33-33 = -14-33

y = -47

7 0

2 years ago

Q2.The two triangles shown below are congruent by ?

dalvyx [7]

Answer:

cccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Segment FG begins at point F(-2, 4) and ends at point G(-2, -3). The segment is translated 3 units left and 2 units up, then ref

Alexus [3.1K]

Answer:

$F'G' = 7$

Step-by-step explanation:

Given

$F = (-2,4)$

$G = (-2,-3)$

Required

Distance of F'G'

The transformation that give rise to F'G' from FG are:

Translation
Reflection

The above transformations are referred to as rigid transformation, and as such the side lengths remain unchanged.

i.e.

$F'G' = FG$

Calculating FG, we have:

$FG = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}$

Where:

$F = (-2,4)$ --- $(x_1,y_1)$

$G = (-2,-3)$ --- $(x_2,y_2)$

$FG = \sqrt{(-2 - -2)^2 + (4 - -3)^2}$

$FG = \sqrt{(0)^2 + (7)^2}$

$FG = \sqrt{0 + 49}$

$FG = \sqrt{49}$

Take positive square root

$FG = 7$

Recall that:

$F'G' = FG$

$F'G' = 7$

6 0

2 years ago

Help!<br> It's a picutre

9966 [12]

Here is your answer

a) 5x-2y= 1

REASON:

6-2(x-y)=3x+5

6-2x+2y= 3x+5

3x+2x-2y= 6-5

5x-2y= 1

HOPE IT IS USEFUL

3 0

2 years ago