Using the <u>normal distribution and the central limit theorem</u>, it is found that the interval that contains 99.44% of the sample means for male students is (3.4, 3.6).
In a normal distribution with mean
and standard deviation
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation
.
In this problem:
- The mean is of
.
- The standard deviation is of
.
- Sample of 100, hence

The interval that contains 95.44% of the sample means for male students is <u>between Z = -2 and Z = 2</u>, as the subtraction of their p-values is 0.9544, hence:
Z = -2:

By the Central Limit Theorem




Z = 2:




The interval that contains 99.44% of the sample means for male students is (3.4, 3.6).
You can learn more about the <u>normal distribution and the central limit theorem</u> at brainly.com/question/24663213
Sorry if this isn’t correct but I think its $11.9
(-3/2, 7/2)
-3/2+7/2=2
7/2=-3/2+5
Answer:
x=9
Step-by-step explanation:
We have been given the following proportion;
x/6 = 6/4
In order to solve for x, we simply make x the subject on the left hand side;
To do this we multiply both sides by 6,
(x/6)*6 = (6/4)*6
x = 36/4
x = 9
The value of x is thus 9