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3 years ago

8

A parameter is defined as the _____.

1 answer:

Sphinxa [80]3 years ago

6 0

Answer: The answer is (c) estimate of a variable, as determined through a sample.

Step-by-step explanation: We are given four different options out of which one gives the perfect definition of a parameter.

In mathematics, a parameter is defined as a constant or a variable in a function that determines a particular form of the function but not its general form. For example, f(x) = k x, where 'k' determines only the gradient of the line described by f(x).

In statistics, a parameter is defined as a variable that enters in the mathematical form of a distribution such that the possible values of the variable correspond to different distributions.

Thus, the correct option is (c) estimate of a variable, as determined through a sample.

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Nastasia [14]

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Step-by-step explanation:

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3 years ago

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Olenka [21]

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4 years ago

According to Lambert's law, the intensity of light from a single source on a flat surface at point P is given by Upper L equal

malfutka [58]

Answer:

(a) $L = k*(1 - sin^{2}(\theta))$

(b) L reaches its maximum value when θ = 0 because cos²(0) = 1

Step-by-step explanation:

Lambert's Law is given by:

$L = k*cos^{2}(\theta)$ (1)

(a) We can rewrite the above equation in terms of sine function using the following trigonometric identity:

$cos^{2}(\theta) + sin^{2}(\theta) = 1$

$cos^{2}(\theta) = 1 - sin^{2}(\theta)$ (2)

By entering equation (2) into equation (1) we have the equation in terms of the sine function:

$L = k*(1 - sin^{2}(\theta))$

(b) When θ = 0, we have:

$L = k*cos^{2}(\theta) = k*cos^{2}(0) = k$

We know that cos(θ) is a trigonometric function, between 1 and -1 and reaches its maximun values at nπ, when n = 0,1,2,3...

Hence, L reaches its maximum value when θ = 0 because cos²(0) = 1.

I hope it helps you!

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3 years ago

Read 2 more answers

1000000000000000000000000000000000000000000000X100/1/222X1

jok3333 [9.3K]

Answer:

4.5045045 x 10^44

Step-by-step explanation:

I just put it into a calculator idk if its even right

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3 years ago