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jok3333 [9.3K]
3 years ago
9

Consider this exponential equation:

Mathematics
1 answer:
ioda3 years ago
4 0

Step-by-step explanation:

F( <em>x</em><em> </em><em>)</em><em> </em><em>=</em><em> </em><em>5</em><em> </em><em>(</em><em>3</em><em>)</em><em> </em><em>^</em><em> </em><em>x</em>

<em>Y</em><em> </em><em>intercept</em><em> </em>

<em>Let</em><em> </em><em>x</em><em> </em><em>=</em><em> </em><em>0</em>

<em>f</em><em>(</em><em>0</em><em>)</em><em> </em><em>=</em><em> </em><em>5</em><em>×</em><em> </em><em>3</em><em> </em><em>^</em><em> </em><em>0</em>

<em>f</em><em>(</em><em>0</em><em> </em><em>=</em><em> </em><em>5</em><em> </em><em>×</em><em> </em><em>1</em>

<em>f</em><em>(</em><em>0</em><em>)</em><em> </em><em>=</em><em> </em><em>5</em>

<em>X</em><em> </em><em>intercept</em><em> </em>

<em>let</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>o</em>

<em>0</em><em> </em><em>=</em><em> </em><em>5</em><em> </em><em>×</em><em> </em><em>3</em><em> </em><em>^</em><em>x</em>

<em>No</em><em> </em><em>x</em><em> </em><em>intercept</em><em>/</em><em> </em><em>zero</em>

<em>therefore</em><em> </em>

<em>Vertical</em><em> </em><em>intercept</em><em> </em><em>(</em><em>0</em><em>;</em><em> </em><em>5</em><em>)</em>

<em>Domain</em><em> </em><em>XER</em>

<em>▪︎</em><em>this</em><em> </em><em>refer</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>values</em><em> </em><em>of</em><em> </em><em>X</em>

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Step-by-step explanation:

Data provided in the question:

p = $3000,

r = 3.5%,

t = 5 years

a) quarterly

number of periods in a year, n = 4

Interest rate per period = 3.5% ÷ 4 = 0.875%

Now,

A = p\times \left( 1 + \frac{r}{n} \right)^{\Large{n \cdot t}}

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b) monthly

number of periods in a year, n = 12

Now,

A = p\times \left( 1 + \frac{r}{n} \right)^{\Large{n \cdot t}}

on substituting the respective values, we get

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A = pe^{r\times t}

on substituting the respective values, we get

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A = $3,573.74

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