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V125BC [204]
2 years ago
6

Please help! proof Given: FA bisects ∠LFK and ∠LAK Prove: FA bisects ∠LJK

Mathematics
1 answer:
serg [7]2 years ago
7 0

Answer:look at the picture below

Step-by-step explanation:

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Please help me
dusya [7]
3(4x - 2) = 2(6x - 3)

12x - 6 = 12x - 6

Add 6 on both sides

12x = 12x

Divide by 12 on both sides

x = x

That means this has infinite solutions. Your answer is B.
4 0
3 years ago
Read 2 more answers
For which independent value do the equations generate the same dependent value? y1=6x-16 , y2=3x-10
Nikitich [7]
The question asks which x-value gives the same y-value for both equations, so if you need the ys to be equal, you can set both equations equal to each other, giving you 6x-16=3x-10. Now, solve for x. 6x-16=3x-10, subtract 3x and add 16, 3x=6, divide 3, x=2. Your answer is x=2.
7 0
3 years ago
4.92 divided by 2.28 give detailed response​
e-lub [12.9K]

Answer:

2.1578

Step-by-step explanation:

5 0
3 years ago
Can someone please help me with math.
romanna [79]
Answer:

I think it’s A
6 0
2 years ago
What is an equation of the line that passes through (-2,3) and is parallel to y=5x + 4.Give your answer in slope intercept form
9966 [12]

Answer:

y= 5x+13

Step-by-step explanation:

<u>Slope- intercept form</u>

y= mx +b, where m is the gradient and b is the y-intercept.

Parallel lines have the same gradient.

y= 5x +4

Gradient of given line= 5

Thus, gradient of line= 5

Subst. m=5 into the equation.

y= 5x +b

To find the value of b, substitute a coordinate

When x= -2, y=3,

3= 5(-2) +b

3= -10 +b

b= 3 +10 <em>(</em><em>+</em><em>1</em><em>0</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>

b= 13

Thus, the equation of the line is y= 5x +13.

8 0
3 years ago
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