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3 years ago

5

If a person is given $1 and invests that $1 for 100 years at 5%, what amount would they be able to withdraw from this account af

ter the 100-year period?

1 answer:

Oksana_A [137]3 years ago

6 0

in 100 years they will be able to withdraw $131.50

1(1.05)^100

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Bryan has 180 feet of fencing to fence off his rectangular garden. He will use the wall of his house as one side of the garden.

DiKsa [7]

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3 years ago

Explain how to solve for coordinates for the equation x + y = 7. Include some coordinates in your answer.

koban [17]

Answer:

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3 years ago

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aleksandrvk [35]

4x+(3x-8)=90

4x+3x-8=90

7x=98

x=98/7

x=14

If x=14,

angle CDJ is:

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3 years ago

Read 2 more answers

A runner maintains constant acceleration after starting from rest as she runs a distance of 60.0 m. The runner's speed at the en

Svet_ta [14]

Answer: $\frac{40}{3}s$

Step-by-step explanation:

This is a typical problem of u.a.r.m. ( uniformly accelerated rectilinear motion). Let's take an eye on the u.a.r.m. equations:

$v(t) = v_{0} + a.t\\x(t) = x_{0} + v_{0}.t + \frac{1}{2}.a.t^{2}$

We know the runner started from rest so we can discard $v_{0}$ as $v_{0} = 0$

Also we can consider she starts at $x_{0} = 0$ .

All we have to do now is replace these values at our equations to obtain:

$v(t) = a.t\\x(t) = \frac{1}{2}.a.t^{2}$

As we are told that the acceleration remains constant, we can then find the time it took for her to run the whole distance as follows:

First we note that the ratio between her velocity and the time it takes for her to run a certain distance is constant. This is:

$\frac{v(t)}{t} = a ; \forall t$

In particular, if we take $t=t_{f}$ where $t_{f}$ is the total time it takes for her to run the whole distance $x(t=t_{f})=60m$

We know that at this point the velocity is:

$v(t=t_{f}) = 9\frac{m}{s}$

So that:

$a = \frac{v(t=t_{f})}{t_{f}} = \frac{9\frac{m}{s}}{t_{f}}$

Now we can replace this in the equation of motion $x(t)$

$x(t=t_{f}) = \frac{1}{2}.a.t^{2} = \frac{1}{2}.\frac{9\frac{m}{s}}{t_{f}}.t_{f}^{2} = 60m$

Where we finally find that

$t_{f} = \frac{40}{3}s$

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3 years ago

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Which of the following represents all solutions of x² - 4x-1=0?

andrey2020 [161]

Answer:

$x=4.23$ or $x=-0..23$

Step-by-step explanation:

Let x be the roots of given equation.

Given.

$x^{2} -4x-1=0$ ------------(1)

The standard form of quadratic equation is.

$ax^{2} + bx+c=0$ -------------(2)

We can solve the roots by this quadratic formula

$x=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}$ -----------(3)

We compare the equation 1 and 2.

where $a=1, b=-4, c=-1$

All values put in the equation 3

$x=\frac{-(-4)\pm\sqrt{(-4)^{2}-4(1)(-1)}}{2(1)}$

$x=\frac{4\pm\sqrt{16+4}}{2}$

$x=\frac{4\pm\sqrt{20}}{2}$

$x=2+\sqrt{5}=4.23\\x=2-\sqrt{5}=-0.23$

5 0

3 years ago