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3 years ago

3x+2(6x)=15 Can you please solve for x? Thanks!

Mathematics

2 answers:

Debora [2.8K]3 years ago

6 0

Answer:

x=1

Step-by-step explanation:

6x x 2=12x + 3x = 15x

15x/15 = 15/15

x = 1

Law Incorporation [45]3 years ago

3 0

Answer:

x=1

Step-by-step explanation:

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What 2 numbers should be used to find 231 - 198 using the 10 method for subtracting quickly in your head?

Airida [17]

Answer: "Count 2 and then count 31 more."

Step-by-step explanation:

We have the equation:

231 - 198

Now, the negative number is kinda ugly, so i will write it as:

200 - 2 = 198

Is a lot easier work with 200 and 2, than with 198.

Then the equation is now:

231 - (200 - 2)

And the left number we also have a "200", so it can be written as:

200 + 31 = 231

As this is a sum, we can ignore the parentheses.

200 + 31 - 200 + 2

31 + 2

Then the correct option is:

"Count 2 and then count 31 more."

4 0

3 years ago

Factor using the trinomial<br> 10.<br> X2 + 13x + 12

Rudik [331]

Answer:

Factoring the trinomial: $x^2+13x+12$ we get the factors $\mathbf{(x+1)(x+12)}$

Step-by-step explanation:

We need to factor the trinomial: $x^2+13x+12$

We can factor the trinomial by breaking the middle term i.e 13x

Such that adding or subtracting gets the both terms we get 13x and multiplying both terms we get 12x^2

We can break 13x as: 12x and x

Adding them we get 13x and multiplying them we get 12x^2

So,

$x^2+13x+12\\=x^2+12x+x+12\\=x(x+12)+1(x+12)\\=(x+1)(x+12)$

So, Factoring the trinomial: $x^2+13x+12$ we get the factors $\mathbf{(x+1)(x+12)}$

8 0

3 years ago

Predict the number of pancakes that would have 48 chocolate chips

Montano1993 [528]

The answer would be 6 number of pancakes. Hope it helps

5 0

3 years ago

Solve the quadratic equation algebraically 5-x<2(x-3)+5

vodka [1.7K]

Answer:

x>2

Step-by-step explanation:

5-x<2(x-3)+5

5-x<2x-6+5

5-x<2x-1

6-x<2x

6<3x

x>2

7 0

2 years ago

Show that the equation x^3+6x-5=0 has a solution between x=0 and x=1

Mnenie [13.5K]

Answer:

Since the value of f(0) is negative and the value of f(1) is positive, then there is at least one value of x between 0 and 1 for which f(x) =0.

Step-by-step explanation:

The equation f(x) given is:

$f(x) = x^3+6x-5$

For x = 0. the value of the expression is:

$f(0) = 0^3+0-5\\f(0) = -5$

For x = 1, the value of the expression is:

$f(1) = 1^3+6-5\\f(1)=2$

Since the value of f(0) is negative and the value of f(1) is positive, then there is at least one value of x between 0 and 1 for which f(x) =0.

In other words, there is at least one solution for the equation between x=0 and x=1.

6 0

3 years ago