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3 years ago

Resuelve las siguientes ecuaciones

Mathematics

1 answer:

N76 [4]3 years ago

3 0

Answer:

Step-by-step explanation:

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What expression is correct?

Mazyrski [523]

Answer: Oliver is correct

Step-by-step explanation:*mine doesn’t have the line and stuff to show u how to explain it*

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4 years ago

To find the square root of a number, you must divide the number by 2. True False

Kaylis [27]

To find the square root of a number you would have to divide it by 2
So yes the answer is true

5 0

4 years ago

Plllllllllllllllllleassssssssseeeeeeeeee help

Vlad1618 [11]

Answer:

1/(5^12 * 32^3 * 9^15)

Step-by-step explanation:

5^-12 = 1/(5^12)

32^-3 = 1/(32^3)

9^-15 = 1/(9^15)

1/(5^12) * 1/(32^3) * 1/(9^15) = 1/(5^12 * 32^3 * 9^15)

8 0

3 years ago

A greenhouse is offering a sale on tulip bulbs because they have inadvertently mixed pink bulbs with red bulbs. If 40% of the b

Zolol [24]

<h3>Answer: 0.8704</h3>

Explanation:

40% of the bulbs are pink, 60% are red

the probability of picking pink is 0.40 and the probability of not picking pink is 0.60

The chances of getting 4 non-pink in a row is 0.6*0.6*0.6*0.6 = 0.6^4 = 0.1296

The complement to this event is getting at least one pink bulb, which has a chance of 1-0.1296 = 0.8704

0.8704 converts to 87.04%

5 0

3 years ago

Math scores on the SAT exam are normally distributed with a mean of 514 and a standard deviation of 118. If a recent test-taker

LuckyWell [14K]

Answer:

Probability that the student scored between 455 and 573 on the exam is 0.38292.

Step-by-step explanation:

We are given that Math scores on the SAT exam are normally distributed with a mean of 514 and a standard deviation of 118.

Let X = Math scores on the SAT exam

So, X ~ Normal( $\mu=514,\sigma^{2} =118^{2}$ )

The z score probability distribution for normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean score = 514

$\sigma$ = standard deviation = 118

Now, the probability that the student scored between 455 and 573 on the exam is given by = P(455 < X < 573)

P(455 < X < 573) = P(X < 573) - P(X $\leq$ 455)

P(X < 573) = P( $\frac{X-\mu}{\sigma}$ < $\frac{573-514}{118}$ ) = P(Z < 0.50) = 0.69146

P(X $\leq$ 2.9) = P( $\frac{X-\mu}{\sigma}$ $\leq$ $\frac{455-514}{118}$ ) = P(Z $\leq$ -0.50) = 1 - P(Z < 0.50)

= 1 - 0.69146 = 0.30854

The above probability is calculated by looking at the value of x = 0.50 in the z table which has an area of 0.69146.

Therefore, P(455 < X < 573) = 0.69146 - 0.30854 = 0.38292

Hence, probability that the student scored between 455 and 573 on the exam is 0.38292.

7 0

4 years ago