Calculate the slope of the line.Please help!!

please help me please if some one answers my question next i will post 100 points free if some one answers this question please

kari74 [83]

Answer:

Step-by-step explanation:

a) the points (0,60) and (6.0) are the intercept points for the graph of the car slowing down ( accelerating in the opposite direction than it's traveling)

we already know the slope of the line b/c that the rate at which it's slowing .. -10 =m which is the slope of the line .. down 10

use the point-slope formula y-y1 = m(x-x1) and plug in either given point for (x1,y1)

b) y -60 = -10(x-0)

y= -10x+60

thats the slope-intercept form of the equation

4 0

2 years ago

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What is the equation of the line in the slope intercept form?

VladimirAG [237]

Answer:

y = mx+b is the equation for slope-intercept form

Step-by-step explanation:

m=slope

x=independent variable

y= y-intercept

3 0

3 years ago

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25 students tried out for the football team, but 40% only made the team. How many of the students made the football team? Provid

Alexxandr [17]

Answer:

B. 10

Step-by-step explanation:

$40\% \: of \: 25 = \frac{40}{100} \times 25 \\ \\ = \frac{40}{4} = 10$

Hence, 10 students made the football team.

6 0

2 years ago

Which number is written in scientific notation? 6 times 10 Superscript 11 12 times 10 Superscript negative 8 0.2 times 10 Supers

Mandarinka [93]

Answer: 6 times 10 Superscript 11

Step-by-step explanation:

Scientific notation is in the form ;

A.0 x $10^{n}$ ,

where :

A = any number from 1 to 9

n = integers , that is , n must be whole numbers

Following this rule , the correct answer is

6 x $10^{11}$

which is 6 times 10 Superscript 11

5 0

3 years ago

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Find the directional derivative of the function at the given point in the direction of the vector v. G(r, s) = tan−1(rs), (1, 3)

alexandr1967 [171]

The <em>directional</em> derivative of $f$ at the given point in the direction indicated is $\frac{5}{2}$ .

<h3>How to calculate the directional derivative of a multivariate function</h3>

The <em>directional</em> derivative is represented by the following formula:

$\nabla_{\vec v} f = \nabla f (r_{o}, s_{o})\cdot \vec v$ (1)

Where:

$\nabla f (r_{o}, s_{o})$ - Gradient evaluated at the point $(r_{o}, s_{o})$ .
$\vec v$ - Directional vector.

The gradient of $f$ is calculated below:

$\nabla f (r_{o}, s_{o}) = \left[\begin{array}{cc}\frac{\partial f}{\partial r}(r_{o},s_{o}) \\\frac{\partial f}{\partial s}(r_{o},s_{o}) \end{array}\right]$ (2)

Where $\frac{\partial f}{\partial r}$ and $\frac{\partial f}{\partial s}$ are the <em>partial</em> derivatives with respect to $r$ and $s$ , respectively.

If we know that $(r_{o}, s_{o}) = (1, 3)$ , then the gradient is:

$\nabla f(r_{o}, s_{o}) = \left[\begin{array}{cc}\frac{s}{1+r^{2}\cdot s^{2}} \\\frac{r}{1+r^{2}\cdot s^{2}}\end{array}\right]$

$\nabla f (r_{o}, s_{o}) = \left[\begin{array}{cc}\frac{3}{1+1^{2}\cdot 3^{2}} \\\frac{1}{1+1^{2}\cdot 3^{2}} \end{array}\right]$

$\nabla f (r_{o}, s_{o}) = \left[\begin{array}{cc}\frac{3}{10} \\\frac{1}{10} \end{array}\right]$

If we know that $\vec v = 5\,\hat{i} + 10\,\hat{j}$ , then the directional derivative is:

$\nabla_{\vec v} f = \left[\begin{array}{cc}\frac{3}{10} \\\frac{1}{10} \end{array}\right] \cdot \left[\begin{array}{cc}5\\10\end{array}\right]$

$\nabla _{\vec v} f (r_{o}, s_{o}) = \frac{5}{2}$

The <em>directional</em> derivative of $f$ at the given point in the direction indicated is $\frac{5}{2}$ . $\blacksquare$

To learn more on directional derivative, we kindly invite to check this verified question: brainly.com/question/9964491

3 0

2 years ago