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Alla [95]
4 years ago
5

Help please! I’m struggling ah sksjkdkkdkd -Alyssa

Mathematics
1 answer:
Maurinko [17]4 years ago
3 0

He would weight 3.745 kg. Dividing it by 1,000 which is what a kg is more to a gram, 1,000 g = 1 kg. If the problem looked like 3,745. then move the dot over by how many zero's there is in 1,000, which is 3. 3.745. And sorry, but I am not sure about your other problem. But if I were to guess, I would say 34 units.

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Which answer shows this equation written in standard form?
Iteru [2.4K]
So first we solve and simplify
pemdas
first parenthasees

9-4(x-y)=-6x+6
distribute using distributeive property of multiplication which is a(b+c)=(ab)+(ac)

so -4(x-y)=-4x+4y

9-4x+4y=-6x+6
add 6x to both sides
9+2x+4y=6
subtract 9 from both sides
2x+4y=-3
only B matches this
B is the correct answer

(I don't know what standard form is but I know what simplified is)
5 0
4 years ago
Sophia determined that the expression Negative (4 x minus 5) + 2 (x minus 3) is equivalent to –2x – 5 by using the steps below.
CaHeK987 [17]

Answer:Hope This Helps ☺️

Step-by-step explanation:

She is not correct because she did not substitute the same number in both expressions in Step 1

Step-by-step explanation:

CASE 1: substitute 1 for x to both sides of the equations

L.H.S

-(4x-5)+2(x-3)

-(4 (1) - 5)+ 2(1-3) = - (-1) + 2(-2) = 1 - 4 = -3

R.H.S

-2x - 5

-2(1) - 5 = -2-5 = -7

Hence for x= 1

-(4x-5)+2(x-3) ≠ -2x -5

Because -3 ≠ -7

CASE 2: substitute -1 for x to both sides of the equations

L.H.S

-(4x-5)+2(x-3)

-(4 (-1) - 5)+ 2(-1-3) = - (-9) + 2(-4) = 9 - 8 = 1

R.H.S

-2x - 5

-2(-1) - 5 = 2-5 = -3

Hence for x= -1

-(4x-5)+2(x-3) ≠ -2x -5

Because 1 ≠ -3

Answer:

She is not correct because she did not substitute the same number in both expressions in Step 1

3 0
3 years ago
Read 2 more answers
Math help please!<br> |120+x| x&lt;-120
In-s [12.5K]

Answer:

-120-x

Step-by-step explanation:

Given:

\displaystyle \large{|120+x| \quad (x < -120)}

This is the same as previous one. Recall modulus property:

\displaystyle \large{|a+x| = \begin{cases} a+x \quad (x \geq  -a) \\ -a-x \quad (x < -a) \end{cases}}

Keep in mind that |x+a| and |a+x| are equal via addition property.

Since the question gives interval of x < -120:

Therefore, the expression is -120-x

4 0
2 years ago
What is the y-value in the solution to this system of linear equations?
Rainbow [258]

Y=17 that the answer


6 0
4 years ago
Read 2 more answers
Find the equation of the line through (- 4, 5) which is perpendicular to the line y = x/4 - 1
iragen [17]

We conclude that the linear equation perpendicular to y = x/4 - 1 and that passes through (-4, 5) is y = -4*x - 11

<h3>How to find the perpendicular line?</h3>

A general linear equation is of the form:

y = a*x + b

Where a is the slope and b is the y-intercept.

Two lines are perpendicular if the slope of one line is equal to the inverse of the opposite of the other slope.

So, if we have:

y = x/4 - 1

The slope is a = (1/4)

The inverse of the opposite is:

a' = -4

Then the perpendicular line is of the form:

y = -4*x + c

Now we want this to pass through the point (-4, 5), then we must have:

5 = -4*-4 + c

5 = 16 + c

5 - 16 = c = -11

We conclude that the linear equation perpendicular to y = x/4 - 1 and that passes through (-4, 5) is y = -4*x - 11

If you want to learn more about linear equations:

brainly.com/question/1884491

#SPJ1

4 0
2 years ago
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