Answer:
282240 ways
Step-by-step explanation:
number of items = 9 different items
Ranking based on worth
<u>determine number of ways to arrange the 9 items such that the 2 most expensive are apart</u>
first step: consider the 2expensive items as 1
∴ number of permutation = [ ( 9 - 2 ) + 1 ]! * 2!
= [ 8 ] ! * 2! = 80640
Total number of permutation/arrangement = 9! = 362880
hence to arrange the 9 items without having the two most expensive items together
= 362,880 - 80640
= 282240 ways
5 6 7 8 9 10 All the positive number are grater than -10 but if it askes for negative you would you -5 -6 -7 -8 -9