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Lynna [10]
3 years ago
13

Jing jing works in a store and she spends some of her time organizing the stationary section. If there are nine different items

on the rack, how many ways can she organize the rack so that the two most expensive items are not together?
Mathematics
1 answer:
Alexus [3.1K]3 years ago
4 0

Answer:

282240 ways

Step-by-step explanation:

number of items = 9 different items

Ranking based on worth

<u>determine number of ways to arrange the 9 items such that the 2 most expensive are apart</u>

first step: consider the 2expensive items as 1

∴ number of permutation = [ ( 9 - 2 ) + 1 ]!  * 2!

                                          = [ 8 ] ! * 2!  = 80640

Total number of permutation/arrangement = 9! = 362880

hence to arrange the 9 items without having the two most expensive items together

= 362,880 - 80640

= 282240 ways

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Please help! i dont understand
kvv77 [185]

QUESTION 1

The given inequality is  

y\leq x-3 and y\geq -x-2.

If (3,-2) is a solution; then it must satisfy both inequalities.

We put x=3 and y=-2 in to both inequalities.

-2\leq 3-3 and -2\geq -3-2.

-2\leq 0:True and -2\geq -5:True

Both inequalities are satisfied, hence (3,-2) is a solution to the given system of inequality.

QUESTION 2

The given inequality is  

y\:>\:-3x+3 and y\:>\: x+2.

If (1,4) is a solution; then it must satisfy both inequalities.

We put x=1 and y=4 in to both inequalities.

4\:>\:-3(1)+3 and 4\:>\: 1+2.

4\:>\:0:True and 4\:>\: 3:True

Both inequalities are satisfied, hence (1,4) is a solution to the given system of inequality.

Ans: True

QUESTION 3

The given inequality is  

y\leq 3x-6 and y\:>\: -4x+2.

If (0,-2) is a solution; then it must satisfy both inequalities.

We put x=0 and y=-2 in to both inequalities.

-2\leq 3(0)-6 and -2\:>\: -4(0)+2.

-2\leq -6:False and -2\:>\:2:False

Both inequalities are not satisfied, hence (0,-2) is a solution to the given system of inequality.

Ans:False

QUESTION 4

The given inequality is  

2x-y\: and x+y\:>\:-1.

If (0,3) is a solution; then it must satisfy both inequalities.

We put x=0 and y=3 in to both inequalities.

2(0)-3\: and 0+3\:>\:-1.

-3\::True and 3\:>\:-1: True

Both inequalities are satisfied, hence (0,3) is a solution to the given system of inequality.

Ans:True

QUESTION 5

The given system of inequality is  

y\:>\:2x-3 and y\:.

If (-3,0) is a solution; then it must satisfy both inequalities.

We put x=-3 and y=0 in to both inequalities.

0\:>\:2(-3)-3 and 0\:.

0\:>\:-9;True and 0\::True

Both inequalities are satisfied, hence (-3,0) is a solution to the given system of inequality.

Ans:True

3 0
3 years ago
Right answers plzzzz
Andrew [12]
D.  

a. 

b. 

hope that helped
5 0
3 years ago
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