Answer:
Step-by-step explanation:
All other things being equal (and there are a lot of other things) the 50 gram mass will show a larger temperature
increase than the 100 gram mass.
Why?
The formula is the same from both masses of water (50 grams and 100 grams)
The amount of heat added is the same. (Instead of using hot water, we'll a hot plate on a very low temperature but above what they are now.).
We'll leave it on until we see a rise in temperature delta(t1) = 10 degrees
mc delta(t) = m1 * c * delta(t1)
m = 100
m1 = 50 grams.
c is going to be divided out
we'll solve for the ratio of delta(t) / delta(t1)
100 * delta(t) = 50 (delta(t1)
100 * delta(t) = 50*10
delta(t) = 50*10/100
delta(t) = 5 degrees.
Though this may look rather convoluted, the result is telling us is that delta(t1) for the 50 gram mass is twice as big as as for the 100 gram mass.
The 100 gram mass only rises 5 degrees.
The 50 gram mass rises 10 degrees.
