All categories

2 years ago

Please help!! And show work please! I'll give brainlist..!

Mathematics

1 answer:

mr_godi [17]2 years ago

6 0

What you put is correct because two negatives make a positive so it would be 5 + 7 making it the greatest value

You might be interested in

If x = -3, calculate the value of: 2xsquared + x

Archy [21]

2 x - 3² + - 3
2 x 9 + - 3
18 - 3
15

6 0

3 years ago

Read 2 more answers

1 2/3 - 3/5 as fraction

densk [106]

Answer:

1 1/15 or 16/15

Step-by-step explanation:

Find the common denominator.

25/15 - 9/15 = 16/15

Have a nice day!!

Hope this helps!!

3 0

2 years ago

The distance between Lincoln, NE, and Boulder, CO, is about 500 miles. The distance between Boulder, CO, and a third city is 200

arlik [135]

Answer:

300 < d < 700

Step-by-step explanation:

on edgenuity 2020

7 0

3 years ago

Find the locus of a point such that the sum of its distance from the point ( 0 , 2 ) and ( 0 , -2 ) is 6.

jok3333 [9.3K]

Answer:

$\displaystyle \frac{x^2}{5}+\frac{y^2}{9}=1$

Step-by-step explanation:

We want to find the locus of a point such that the sum of the distance from any point P on the locus to (0, 2) and (0, -2) is 6.

First, we will need the distance formula, given by:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Let the point on the locus be P(x, y).

So, the distance from P to (0, 2) will be:

$\begin{aligned} d_1&=\sqrt{(x-0)^2+(y-2)^2}\\\\ &=\sqrt{x^2+(y-2)^2}\end{aligned}$

And, the distance from P to (0, -2) will be:

$\displaystyle \begin{aligned} d_2&=\sqrt{(x-0)^2+(y-(-2))^2}\\\\ &=\sqrt{x^2+(y+2)^2}\end{aligned}$

So sum of the two distances must be 6. Therefore:

$d_1+d_2=6$

Now, by substitution:

$(\sqrt{x^2+(y-2)^2})+(\sqrt{x^2+(y+2)^2})=6$

Simplify. We can subtract the second term from the left:

$\sqrt{x^2+(y-2)^2}=6-\sqrt{x^2+(y+2)^2}$

Square both sides:

$(x^2+(y-2)^2)=36-12\sqrt{x^2+(y+2)^2}+(x^2+(y+2)^2)$

We can cancel the x² terms and continue squaring:

$y^2-4y+4=36-12\sqrt{x^2+(y+2)^2}+y^2+4y+4$

We can cancel the y² and 4 from both sides. We can also subtract 4y from both sides. This leaves us with:

$-8y=36-12\sqrt{x^2+(y+2)^2}$

We can divide both sides by -4:

$2y=-9+3\sqrt{x^2+(y+2)^2}$

Adding 9 to both sides yields:

$2y+9=3\sqrt{x^2+(y+2)^2}$

And, we will square both sides one final time.

$4y^2+36y+81=9(x^2+(y^2+4y+4))$

Distribute:

$4y^2+36y+81=9x^2+9y^2+36y+36$

The 36y will cancel. So:

$4y^2+81=9x^2+9y^2+36$

Subtracting 4y² and 36 from both sides yields:

$9x^2+5y^2=45$

And dividing both sides by 45 produces:

$\displaystyle \frac{x^2}{5}+\frac{y^2}{9}=1$

Therefore, the equation for the locus of a point such that the sum of its distance to (0, 2) and (0, -2) is 6 is given by a vertical ellipse with a major axis length of 3 and a minor axis length of √5, centered on the origin.

5 0

3 years ago

Read 2 more answers

A salad made such that the difference between twice the ounces of greens and the ounces of carrots is at least 3. Also, the sum

kap26 [50]

Answer:

3rd graph down

Step-by-step explanation:

greens are x and carrots are y in my equations

2x - y >= 3

x + 2y < 4

The first equation is solid and will highlight everything to the right of it because it is a >

the second is dashed and will highlight everything to the left of it because it is a <

the only 2 graphs that show this are 1 and 3

looking at the points you can see that the points for the solid line are both the same so ignore those and go to the dashed lined ones.

on the first graph the points are (0,4)

plugging those into our equation gives us 0 + 2*4 <4

or 8<4 which doesnt make sense making 3 the correct graph

(sorry my answer wasnt posting so i had to start over and make it less detailed, but comment if you need any explanation)

4 0

3 years ago

Read 2 more answers