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baherus [9]
3 years ago
12

If x+y=6 and xy =2find x³+y³(please help me fast with explanation also please) T^T​

Mathematics
1 answer:
Maurinko [17]3 years ago
6 0

Answer: x³+y³=180

Step-by-step explain:                                                                                            let's remember the formula                                                                                 x³+y³=(x+y)(x²-xy+y²) and also  x³+y³=(x+y)³-3xy(x+y)                                              then                                                                                      \displaystyle\boldsymbol{ x^3+y^3=\underbrace{(x+y)^3}_{6}-3\underbrace{xy}_{2}\underbrace{(x+y)}_6}=\\\\6^3-3\cdot 2\cdot 6=216-36=180                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                

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Step-by-step explanation:

x y and z are three consecutive even numbers

it means that you can write y = x + 2

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so the solutions are

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6 0
3 years ago
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