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Irina-Kira [14]
3 years ago
6

The planet Mars could be a future destination for the U.S. space program. Assume that Mars is a perfect sphere. Its surface area

is about 145 million square kilometers. What is the radius of Mars at its equator? Round to the hundreds place.
||| Answer choices:
A) 4,500 km
B) 2,200 km
C) 5,000 km
D) 3,400 km |||
Mathematics
1 answer:
Arlecino [84]3 years ago
4 0
Surface area of a sphere is  4 times pi timers radius^2
aprox pi=3.14

so surface area=145,000,000

145,000,000=4 times 3.14 times rdaius^2
145,000,000=12.56 times radius^2
divide both sdies by 12.56
11544585.987=r^2
square root both sides
3397.73=radius

round to the hundreds
3397 rounded to the hundreds
3400

the answer is D 3,4000 km
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The perimeter of a rectangle is equal to 163 yard. The width is 8 more than twice the length. Find the length and width.​
Sedaia [141]

Answer:

l = 29.4 yards

w = 66.8 yards

General Formulas and Concepts:

  • Order of Operations: BPEMDAS
  • Perimeter of a Rectangle: P = 2w + 2l

Step-by-step explanation:

<u>Step 1: Define</u>

P = 163 yards

w = 2l + 8

l = l

<u>Step 2: Set up equation</u>

P = 2w + 2l

163 = 2(2l + 8) + l

<u>Step 3: Solve for </u><em><u>l</u></em>

  1. Distribute 2:                              163 = 4l + 16 + l
  2. Combine like terms:                 163 = 5l + 16
  3. Subtract 16 on both sides:        147 = 5l
  4. Divide both sides by 5:             147/5 = l
  5. Rewrite:                                      l = 147/5
  6. Evaluate:                                    l = 29.4 yards

<u>Step 4: Find </u><em><u>w</u></em>

  1. Define:                    w = 2l + 8
  2. Substitute:              w = 2(29.4) + 8
  3. Multiply:                  w = 58.8 + 8
  4. Add:                        w = 66.8 yards
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find the length of the line segment with end points (7,2) and (-4,2) explain how you arrived at your solution
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Answer:

<h2>11 units</h2>

Step-by-step explanation:

Method 1:

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

We have the points (7, 2) and (-4, 2). Substitute:

d=\sqrt{(2-2)^2+(-4-7)^2}=\sqrt{0^2+(-11)^2}=\sqrt{11^2}=11

Method 2:

Look at the picture. Mark points in the coordinate system.

Read the length of the segment.

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