Answer:
B. 0.0122
Step-by-step explanation:
According to the given data the claim is:
"Proportion of students who went to the movie theater last weekend is greater than 0.2"
Since, the word "greater than" is used in the claim, this claim will be our alternate hypothesis and the hypothesis test will be a one-tailed test i.e. Right tailed test because of the word "greater than".
We are given that the hypothesis test was conducted for a random sample of 100 students and it yielded a z-value of 2.25. We have to find the p-value associated with this z-score
So, we have to find p-value corresponding to z-score of 2.25 and Right Tailed Test. We have to use z-table for this purpose and find the probability of z score being greater than 2.25. From the z-table this value comes out to be:
p-value = 0.0122
Therefore, option B gives the correct answer.
Factored: 4 ( a + 2c - 2)
Standard form/simplified : 4a + 8c - 8
4 is your answer
3 x 4 = 12
15 x 4 = 60
so 4 is the amount
hope this helps
1/7 *2 =2/7 take denominator with 1 over it and multiply by numerator
