PLS HELP I DONT KNOW THE ANSWERSSSS
2 answers:
You might be interested in
This is simple!
To begin with, arrange all the numbers in order.
#1
5, 5, 20, 20, 25, 30, 35
Mean: add all the numbers together and divide it by how many numbers are there
5+5+20+20+25+30+35=140
there are 7 numbers
Mean:
= 20
Median: The middle number, if the set of numbers have an odd number, then the one in between is the median, if there it is an even number, then the mean of the two in-between numbers is the median.
Median: 20
Mode: The most repeated numbers
Mode: 5 and 20
Range: Highest number - lowest number
Range: 35 - 5
30
#2
Order: 44, 48, 48, 49, 59, 61, 63, 68
Mean: 440 (sum of all numbers)
there are 8 numbers in total
= 55
Median: there are 8 numbers so, the mean of the in-between numbers will be the median
49+59=108
2 numbers
= 54
Mode: 48
Range = 68 - 44 = 24
To begin with, arrange all the numbers in order.
#1
5, 5, 20, 20, 25, 30, 35
Mean: add all the numbers together and divide it by how many numbers are there
5+5+20+20+25+30+35=140
there are 7 numbers
Mean:
Median: The middle number, if the set of numbers have an odd number, then the one in between is the median, if there it is an even number, then the mean of the two in-between numbers is the median.
Median: 20
Mode: The most repeated numbers
Mode: 5 and 20
Range: Highest number - lowest number
Range: 35 - 5
30
#2
Order: 44, 48, 48, 49, 59, 61, 63, 68
Mean: 440 (sum of all numbers)
there are 8 numbers in total
Median: there are 8 numbers so, the mean of the in-between numbers will be the median
49+59=108
2 numbers
Mode: 48
Range = 68 - 44 = 24
Answer:
A score of 150.25 is necessary to reach the 75th percentile.
Step-by-step explanation:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
A set of test scores is normally distributed with a mean of 130 and a standard deviation of 30.
This means that
What score is necessary to reach the 75th percentile?
This is X when Z has a pvalue of 0.75, so X when Z = 0.675.
A score of 150.25 is necessary to reach the 75th percentile.