Basically, we need to find the diagonal of the square. Once we have the diagonal, we need to find if it's more or less than 11 cm, which is diameter of the circle.
This is the formula we'll use:
a²+b²=c²
Since it's a square, a and b are the same.
7²+7²=c²
49+49=c²
98=c²
√98=c
c=9.8995
So, the diagonal is 9.8995
9.8995<11
So, since the diagonal of the square is 9.8995 cm, it is less than the circumference of the circle meaning that it will fit in to the circle without touch the circle's circumference.
Answer:
Explanation:
The statement is expressed as
y
∝
1
x
inverse means
1
variable
To convert to an equation introduce k, the constant of variation.
y
=
k
×
1
x
⇒
y
=
k
x
To find k use the given condition that y = 8 when x = 4
8
=
k
4
⇒
k
=
4
×
8
=
32
⇒
equation is
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
∣
∣
∣
2
2
y
=
32
x
2
2
∣
∣
∣
−−−−−−−−−−−−
x
=
16
→
y
=
32
16
⇒
y
=
2
when
x
=
16
Answer:
use symblaob
Step-by-step explanation:
on g_o_o_g_l_e
Answer:
Distance=9.43 units
Step-by-step explanation:
When you have two coordinates and you need to find the distance between them, you can use the distance formula.
D=sqrt(7-2)^2+(3-(-5))^2
D=sqrt(5^2+8^2)
D=sqrt(25+64)
D=sqrt89
D=9.43, rounded to the nearest hundredth.
Therefore, your distance would be 9.43 units.
I hope this helped! Have a good rest of your day~
What are the numbers that showed be in the ratio? I would love to help