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professor190 [17]
2 years ago
10

Solve for a brainliest in 10 min

Mathematics
1 answer:
horsena [70]2 years ago
8 0

1)x+8=16

x= 16-8

x=8

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Which set of integers is a Pythagorean triple?
Vsevolod [243]

Answer:

5,12,13

Step-by-step explanation:

4 0
3 years ago
Solve for j. 144j2 + 21 = 85
Sphinxa [80]

Answer:

2/3

Step-by-step explanation:

I assume the 2 after the j is a square. So, we bring the 21 to the other side by subtracting it from both sides, getting 144j^2=64. Now we divide to get 64/144 = j^2. Make sure NOT to simplify it, it's perfect right now. The square root of that is \sqrt{64}/ \sqrt{144}, or 8/12, which we can now simplify to 2/3. Hope this helps!

5 0
3 years ago
Determine a series of transformations that would map polygon ABCDE onto polygon A’B’C’D’E
zalisa [80]

Answer:

Reflected across x-axis followed by a dilation with a scale factor of 2 about the origin.

Step-by-step explanation:

It's clear from the graph,

Polygon ABCDE is reflected across x-axis then dilated so that it overlaps polygon A'B'C'D'E'

Let's choose a point A having coordinates (-2, -1)

By reflecting point A across x-axis,

Rule to be followed for the reflection,

(x, y) → (x, -y)

By this rule, coordinates of the image point A will be,

A(-2, -1) → A"(-2, 1)

Now point A"(-2, 1) has been dilated by a scale factor = k to form an image points A'(-4, 2).

Rule for the dilation of a point about the origin is,

A"(x, y) → A'(kx, ky)

A"(-2, 1) → A'(-2k, k)

Since, coordinates of point A' are (-4, -2),

Therefore, -2k = -4

k = 2

k = 2

Hence, polygon ABCDE was reflected across x-axis followed by a dilation with a scale factor of 2 about the origin to form polygon A'B'C'D'E'.

3 0
3 years ago
B is the midpoint of ac. Ab = x+9 and bc = 3x-7 find x and ac
natali 33 [55]

To solve this problem, we need to know 2 relationships:

<h2>1. AC = AB + BC</h2>

The distance of AC is the sum of AB and BC.

AC = AB + BC

We know this since the distance of going from A to C (AC) is the same as going from A to B (AB), then B to C (BC).

<h2>2. AB = BC</h2>

The distance of AB is the same as AC.

AB = BC

We know this since B is in the middle of AC, so the distance from B to A (BA) is the same as the distance from B to C (BC).

You can see the attached image (at the bottom) for a visualization of this.

<h2>Putting them together</h2>

Since we know the values of AB and BC...

AB = x+9\\BC = 3x-7

...we can put these values into our 2nd equation and solve for x:

AB = BC\\x + 9 = 3x -7

Add 7 to both sides:

x + 16 = 3x

Subtract x from both sides:

16 = 2x

Divide both sides by 2:

8 = x\\x = 8

Knowing x, we can find the distance of AC using our first equation.

AC = AB + BC

Let's put in the values of AB and BC:

AC = (x+9) + (3x-7)

Before we put in x = 8, we can simplify this:

AC = (x+9) + (3x-7)\\AC = x + 9 + 3x -7\\AC = x + 3x + 9 -7\\AC = 4x + 9 - 7\\AC = 4x+2

We group x and 3x and add those together. Then we subtract 7 from 9.

With this equation, we can put in x = 8:

AC = 4x +2\\AC = 4*8 + 2

Since 4 * 8 = 32:

AC = 4 * 8 + 2\\AC = 32 + 2\\AC = 34

Finally, we have found both x and AC.

<h2>Answer</h2>

x = 8

AC = 34

7 0
3 years ago
Help me please I will give brainliest
ExtremeBDS [4]
The correct answer would be B because it is is written in correct simplified format
8 0
3 years ago
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