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Vedmedyk [2.9K]
3 years ago
13

Click here please. The problems are in picture format

Mathematics
1 answer:
padilas [110]3 years ago
4 0

First picture:

You got the first two right (good job!), so I'll just tackle the third one. If you have to compute f(x-4), it means that you have to substitute x-4 in place of x. Differently from the first two points, this will generate a new function, rather than a specific value:

f(x) = \sqrt{x+4}+2 \implies f(x-4) = \sqrt{(x-4)+4}+2 = \sqrt{x}+2

Second picture:

Given the point (x,y) highlighted in the picture, you can deduce that the base is 2x units long (since it spans from (-x,0) to (x,0)) and the height is y units long (because it spans from (x,0) to (x,y)). So, the area of the rectangle is the multiplication between base and height:

A = 2xy

But we know that y=f(x)=\sqrt{36-x^2}, so we have

A = 2x\sqrt{36-x^2}

The domain of this function is given by the domain of the square root: we want its argument to be non, negative, so we have

36-x^2 \geq 0 \iff x^2 \leq 36 \iff -6 \leq x \leq 6

But since the problem is symmetric, the answer is

0 \leq x \leq 6

You can only see the answer 0 < x < 6 because, if you choose x=0 or x=6, the rectangle degenerates to a segment, and your exercise doesn't like this scenario, apparently

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