Answer:
It is not normally distributed as it has it main concentration in only one side.
Step-by-step explanation:
So, we are given that the class width is equal to 0.2. Thus we will have that the first class is 0.00 - 0.20, second class is 0.20 - 0.40 and so on(that is 0.2 difference).
So, let us begin the groupings into their different classes, shall we?
Data given:
0.31 0.31 0 0 0 0.19 0.19 0 0.150.15 0 0.01 0.01 0.19 0.19 0.53 0.53 0 0.
(1). 0.00 - 0.20: there are 15 values that falls into this category. That is 0 0 0 0.19 0.19 0 0.15 0.15 0 0.01 0.01 0.19 0.19 0 0.
(2). 0.20 - 0.40: there are 2 values that falls into this category. That is 0.31 0.31
(3). 0.4 - 0.6 : there are 2 values that falls into this category.
(4). 0.6 - 0.8: there 0 values that falls into this category. That is 0.53 0.53.
Class interval frequency.
0.00 - 0.20. 15.
0.20 - 0.40. 2.
0.4 - 0.6. 2.
Im not too sure with these, but this is what i got
11. 39.90
12.16
13.182.8
14.220
15.499
16.19.5
5+2=7 which means there will be 7 zeros so it is 10000000 times greater than
1/3 + 1/6
---Find a common denominator, or the least common multiple of the given denominators. In this case, that would be 6.
1/3 = 2/6
1/6 = 1/6
---Now add the fractions
2/6 + 1/6
3/6
---Simplify/Reduce the fraction
3/6
1/2
Answer: 1/2
1/3 + 1/6 = 2/6 + 1/6 = 3/6 (or 1/2)
Hope this helps!
48 is the correct answer because your going to only do the square