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vazorg [7]
2 years ago
10

Burt ran the length of the trail in his town’s park. There are 9 parts to the trail, and each part is the same length. Burt ran

a total of 1.8 kilometers.
What is the length of each part of the trail?
Mathematics
1 answer:
ikadub [295]2 years ago
4 0

Answer:

.2 kilometers

Step-by-step explanation:

Since there are 9 parts to the trail and the total is 1.8 kilometers, just divide the total by how many parts. 1.8 divided by 9 is .2 so the length of each part of the trail is .2 kilometers

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d1i1m1o1n [39]

Answer:

Step-by-step explanation:

(a - b)(a +b) = a² - b²

1 - Sin² A = Cos² A

LHS = \frac{1}{1- Sin A} + \frac{1}{1 + Sin A}\\\\= \frac{1*(1 + Sin A)}{(1- Sin A)(1 + Sin A)} + \frac{1*(1- Sin A)}{(1 + Sin A)(1- Sin A)}\\\\= \frac{1 + Sin A+ 1 - Sin A}{1^{2}-  Sin^{2} A}\\\\= \frac{2}{1 - Sin^{2} A}\\\\= \frac{2}{Cos^{2} A}\\\\= 2 Sec^{2} A

2)  Sec² A - Tan² A = 1

LHS = \frac{1}{Sec A - Tan A}\\\\=\frac{1*(Sec A + Tan A)}{(Sec A -  Tan A)(Sec A + Tan A)}\\\\=\frac{Sec A + Tan A}{Sec^{2} A - Tan^{2} A}\\\\=\frac{Sec A + Tan A }{1}\\\\= Sec A + Tan A = RHS\\\\\\

3) LHS  = Cosec² A + Cot² A

             = Cosec² A +  Cosec² A - 1

            = 2Cosec² A - 1   = RHS

4) LHS = \frac{Sec A}{Cos A}- \frac{Tan A}{Cot A}\\\\          = Sec A*\frac{1}{Cos A}-Tan A*\frac{1}{Cot A}\\\\ = Sec A * Sec A - Tan A * Tan A\\\\= Sec^{2} A - Tan^{2} A \\\\= 1

3 0
3 years ago
A high school football team won 80% of the games they played. If they played 35 games, how many games did they win?
crimeas [40]

Step-by-step explanation:

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let x be total much won

80\% = x \times 100\% \div 35 \\  x= 35 \times 80 \div 100 \\ x = 7 \times 4 \\ x = 28

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3 years ago
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Calculation:

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The simple interest accumulated

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at a rate of 5% per year

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Answer:

No answer

Step-by-step explanation:

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