


with that template in mind, let's see, it went to the right 2 units, and then up 3 units.
that simply means, C = -2, D = 3.
Answer:
B(2,3),C(2,-3)
Step-by-step explanation:
On y-axis symmetry有手就行
Answer:
a. 1.2
b. 0.83
c. 17 min
Step-by-step explanation:
Answer:
i believe the bottom is a <em>irregular quadrilateral </em>and the first one is a <em>parallelogram </em>
Step-by-step explanation: