Answer:
A. b(w) = 80w +30
B. input: weeks; output: flowers that bloomed
C. 2830
Step-by-step explanation:
<h3>Part A:</h3>
For f(s) = 2s +30, and s(w) = 40w, the composite function f(s(w)) is ...
b(w) = f(s(w)) = 2(40w) +30
b(w) = 80w +30 . . . . . . blooms over w weeks
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<h3>Part B:</h3>
The input units of f(s) are <em>seeds</em>. The output units are <em>flowers</em>.
The input units of s(w) are <em>weeks</em>. The output units are <em>seeds</em>.
Then the function b(w) above has input units of <em>weeks</em>, and output units of <em>flowers</em> (blooms).
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<h3>Part C:</h3>
For 35 weeks, the number of flowers that bloomed is ...
b(35) = 80(35) +30 = 2830 . . . . flowers bloomed over 35 weeks
There are 123 Asians, 25 Africans, 21 Europeans and 8 Americans in the village.
To determine the number of Asians, Africans, Europeans, and Americans in the village, the following calculation must be performed:
- A.S + A.F + E.U + A.M = 177
- A.S = A.F + E.U + 69
- E.U - A.M = 13
- E.U = A.M + 13
- 2A.F = E.U + A.M + 29
- A.F + E.U + 69 + A.F + E.U + A.M = 177
- A.F + A.M + 13 + 69 + A.F + A.M + 13 + A.M = 177
- 2A.F + 3A.M = 177 - 13 - 13 - 69
- E.U + A.M + 29 + 3A.M = 82
- A.M + 13 + A.M + 29 + 3A.M = 82
- 5A.M = 82 - 13 - 29
- A.M = 40/5
- A.M = 8
- E.U = 8 + 13 = 21
- A.F = (21 + 29) / 2 = 25
- A.S = 177 - 25 - 21 - 8 = 123
Therefore, there are 123 Asians, 25 Africans, 21 Europeans and 8 Americans in the village.
Learn more about maths in brainly.com/question/25818763
41.803 is 42 rounded to the nearest whole number because when you go past .5 you round to the nearest highest number, but when your below .5 then you round to the nearest lowest number.
A bar graph would be a better choice because it is able to show how often he/she has gotten a good score.
