Answer:
A) Cross-sectional
Step-by-step explanation:
A cross-sectional study is a type of study that involves the data i.e. taken from a population for a specific time period.
Here study shows the peoples interest in variables that are be chosen
In the given situation, since a town obtains a data of the current employment for 10,000 of its total citizens
So this represents the cross-sectional
hence, the correct option is A.
Cross-sectional
Answer:
Start at (0,0) and go down six and one over.
Step-by-step explanation:
Start at (0,0) and go down six and one over and place a dot and remember the line has to be pointing down.
Answer:
⣠⣴⣶⣿⠿⢿⣶⣶⣦⣄⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⣼⡿⠋⠁⠀⠀⠀⢀⣈⠙⢿⣷⡄⠀⠀ ⠀⠀⠀⠀⢸⣿⠁⠀⢀⣴⣿⠿⠿⠿⠿⠿⢿⣷⣄⠀ ⠀⢀⣀⣠⣾⣿⡇⠀⣾⣿⡄⠀⠀⠀⠀⠀⠀⠀⠹⣧ ⣾⡿⠉⠉⣿⠀⡇⠀⠸⣿⡌⠓⠶⠤⣤⡤⠶⢚⣻⡟ . ⣿⣧⠖⠒⣿⡄⡇⠀⠀⠙⢿⣷⣶⣶⣶⣶⣶⢿⣿⠀ . ⣿⡇⠀⠀⣿⡇⢰⠀⠀⠀⠀⠈⠉⠉⠉⠁⠀⠀⣿⠀. ⣿⡇⠀⠀⣿⡇⠈⡄⠀⠀⠀⠀⠀⠀⠀⠀⢀⣿⣿⠀ ⣿⣷⠀⠀⣿⡇⠀⠘⠦⣄⣀⣀⣀⣀⣀⡤⠊⠀⣿⠀ ⢿⣿⣤⣀⣿⡇⠀⠀⠀⢀⣀⣉⡉⠁⣀⡀⠀⣾⡟⠀ ⠀⠉⠛⠛⣿⡇⠀⠀⠀⠀⣿⡟⣿⡟⠋⠀ * ° * • ☆ ° .°• * ✯ ☄ ☆ ★ * ° * °· * . • ° ★ • ☄ ☄ ▁▂▃▄▅▆▇▇▆▅▄▃▁
⣠⣴⣶⣿⠿⢿⣶⣶⣦⣄⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⣼⡿⠋⠁⠀⠀⠀⢀⣈⠙⢿⣷⡄⠀⠀ ⠀⠀⠀⠀⢸⣿⠁⠀⢀⣴⣿⠿⠿⠿⠿⠿⢿⣷⣄⠀ ⠀⢀⣀⣠⣾⣿⡇⠀⣾⣿⡄⠀⠀⠀⠀⠀⠀⠀⠹⣧ ⣾⡿⠉⠉⣿⠀⡇⠀⠸⣿⡌⠓⠶⠤⣤⡤⠶⢚⣻⡟ . ⣿⣧⠖⠒⣿⡄⡇⠀⠀⠙⢿⣷⣶⣶⣶⣶⣶⢿⣿⠀ . ⣿⡇⠀⠀⣿⡇⢰⠀⠀⠀⠀⠈⠉⠉⠉⠁⠀⠀⣿⠀. ⣿⡇⠀⠀⣿⡇⠈⡄⠀⠀⠀⠀⠀⠀⠀⠀⢀⣿⣿⠀ ⣿⣷⠀⠀⣿⡇⠀⠘⠦⣄⣀⣀⣀⣀⣀⡤⠊⠀⣿⠀ ⢿⣿⣤⣀⣿⡇⠀⠀⠀⢀⣀⣉⡉⠁⣀⡀⠀⣾⡟⠀ ⠀⠉⠛⠛⣿⡇⠀⠀⠀⠀⣿⡟⣿⡟⠋⠀ * ° * • ☆ ° .°• * ✯ ☄ ☆ ★ * ° * °· * . • ° ★ • ☄ ☄ ▁▂▃▄▅▆▇▇▆▅▄▃▁
Answer: h(t) = 20 + 32t - 16t²
Explanation:
The function that models the motion of an object thrown in the air (vertically) is:
h(t) = H + Vo × t - (1/2) g×t²
Where:
H is the initial height = 20 feet
Vo is the inital velocity = 32 ft/s (positive if it is upward)
g is gravity acceleration ≈ 32 ft/s²
t is the time
Substitute values:
h(t) = 20 + 32t - 32t² / 2
h(t) = 20 + 32t - 16t²
That is the answer.
There is no given data table but based on the question, the reaction is
xy <=> x + y
If we let M as the initial concentration of xy and c as the in the concentration after the dissociation, then we can use the ICE method
xy <=> x + y
I M
C -c c c
-----------------------------
E M-c c c
Solve for c using
Kc = c(c) / (M - c)
And the concentration of the xy, x, and y can then be determined