2(y+1) = 3 LCD is 4
2*y + 2*1 = 3
2y + 2 = 3
2y = 3 - 2
2y = 1
y = 1 / 2
What is f(x) when given the points (0,-5)
1 answer:
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2(y+1) = 3 LCD is 4
2*y + 2*1 = 3
2y + 2 = 3
2y = 3 - 2
2y = 1
y = 1 / 2
Answer:
<u>AP = 13</u>
Step-by-step explanation:
See the attached figure.
CD = 10 and XY = 24
Line XY bisects and is perpendicular to AB and CD
∴ XY bisects at Y
∴ CY = 0.5 CD = 0.5 * 10 = 5
And from the geometry of the shape
P is the midpoint of XY
∴ XP = YP = 0.5 XY = 0.5 * 24 = 12
XY is perpendicular to CD
∴ ΔPYC is a right triangle at Y
∴ PC (hypotenuse) =
From the figure AP = PC = 13
