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Gennadij [26K]
3 years ago
15

Two positive, consecutive, odd integers have a product of 143. set up an equation to then solve for the integers.

Mathematics
1 answer:
mixer [17]3 years ago
6 0

Answer:

Step-by-step explanation:

Let (2n-1) and (2n+1) be the consecutive, odd numbers.

(2n-1)(2n+1) = 143

4n² - 1 = 143

4n² = 144

n² = 36

n = 6

2n-1 = 11

2n+1 = 13

The numbers are 11 and 13.

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Which equation represents an exponential function that passes through the point (2, 36)?
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Answer:

The exponential function that passes through (2,36) is:

f(x)=4\times 3^x.

Step-by-step explanation:

We are asked to find which function passes through the point (2,36).

i.e. we will put the input value '2' in the following given functions and check which gives the output value as '36'.

1)

f(x)=4\times 3^x

now we put x=2.

f(2)=4\times 3^2\\\\f(2)=4\times 9\\\\f(2)=36

hence option 1 is correct.

2)

f(x)=4\times x^3

Now we put x=2.

f(2)=4\times 2^3\\\\f(2)=4\times 8\\\\f(2)=32

Hence, option 2 is incorrect.

3)

f(x)=6\times 3^x

Now we put x=2

f(2)=6\times 3^2\\\\f(2)=6\times 9\\\\f(x)=54

Hence, option 3 is incorrect.

4)

f(x)=6\times x^3

Now we put x=2.

f(2)=6\times 2^3\\\\f(2)=6\times 8\\\\f(2)=48

Hence, option 4 is incorrect.

Hence, option 1) is correct.

i.e. The exponential function that passes through (2,36) is:

f(x)=4\times 3^x

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