All categories

3 years ago

George says that 4+ a +a+a+b+b=24ab

Mathematics

1 answer:

antoniya [11.8K]3 years ago

4 0

Answer:

3a+2b+4

Step-by-step explanation:

24ab indicates that there is 24 of unit ab which there is not. there is 4+ 3a+2b

You might be interested in

Zara filled up her car with 15 gallons of gas. If Zara paid $33.00, what was the price per gallon of gas?

djyliett [7]

Answer:

$2.20 per gallon.

Step-by-step explanation:

That is 33/15 = $2.20 per gallon.

5 0

3 years ago

Read 2 more answers

Solve 42x = 7{x-1) How do I solve this problem

Nimfa-mama [501]

Answer:

-1/5

Step-by-step explanation:

42x=7[x-1]

42x=7x-7

42x-7x=-7

35x=-7

x=-1/5

3 0

3 years ago

What represents 2 to the second power, 3 to the second power and five

Mkey [24]

2x2=4
3x3=9
5x5=10
Because with powers it is the number times itself not the number times the power. So if i had 5 to the third power it would be 5x5x5=? 5x5=10x5=50 therefore 5 to the third power is 50
I hope this helps!

4 0

3 years ago

Read 2 more answers

12 (2 -2)+32 = (x +6) +2

Anestetic [448]

Answer: x = 24

Step-by-step explanation:

Hey there! I will give the following steps, if you have any questions feel free to ask me in the comments below.

Step 1: Remove parentheses.

12 (2 − 2) + 32 = $x$ + 6 + 2

Step 2: Simplify 2 − 2 to 0.

12 × 0 + 32 = $x$ + 6 + 2

Step 3: Simplify 12 × 0 to 0.

0 + 32 = $x$ + 6 + 2

Step 4: Simplify 0 + 32 to 32.

32 = $x$ + 6 + 2

Step 5: $x$ + 6 + 2 to $x$ + 8.

32 = $x$ + 8

Step 6: Subtract 8 from both sides.

32 − 8 = $x$

Step 7: Simplify 32 − 8 to 24.

24 = $x$

Step 8: Switch sides.

$x$ = 24

~I hope I helped you! :)~

8 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!

liberstina [14]

Answer: C) x = 3, (x = 2 is an extraneous solution)

Step-by-step explanation:

$\frac{x}{x-1}$ - $\frac{1}{x-2}$ = $\frac{2x-5}{x^{2}-3x+2}$

$\frac{x}{x-1}$ - $\frac{1}{x-2}$ = $\frac{2x-5}{(x-1)(x-2)}$

Restrictions: Denominator cannot equal zero (x - 1 ≠ 0) and (x - 2 ≠ 0), so x ≠ 1 and x ≠ 2

$(x - 1)(x - 2)\frac{x}{x-1}$ - $(x - 1)(x - 2)\frac{1}{x-2}$ = $(x - 1)(x - 2)\frac{2x-5}{(x-1)(x-2)}$

x(x - 2) - 1(x - 1) = 2x - 5

x² - 2x - x + 1 = 2x - 5

x² - 3x + 1 = 2x - 5

-2x + 5 -2x + 5

x² - 5x + 6 = 0

(x - 2)(x - 3) = 0

x - 2 = 0 x - 3 = 0

x = 2 x = 3

NOTE: x = 2 is an extraneous solution because it is one of the restricted values.

4 0

3 years ago