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2 years ago

What is the square root of 243 reduced?

Mathematics

1 answer:

allsm [11]2 years ago

6 0

Answer:

9is√3

Step-by-step explanation:

I think I don't really know but that's my answer

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It is based on ratios

12345 [234]

Answer:

Gianna makes $18 per hour.

Step-by-step explanation:

Given Gianna makes 90$ for 5 hours. That means she should make $\frac{90}{5}$ $ = 18$ every hour.

Therefore we have:

HOURS DOLLARS

1 18

2 36

3 54

4 72

5 90

6 108

7 126

For the tabular column mark Hours on the x - axis and Dollars on the Y - axis. It can be plotted from the above table easily.

If Gianna works for 8 hours she would have made 8 X 18 = 144$.

So, she will earn 144$ in 8 hours.

To make 60$ she would have to work $\frac{60}{18}$ hours = 3.33 hours.

3 0

2 years ago

Make t as the subject!! HELP MEE

Umnica [9.8K]

Answer:

t = (p^2/mn) - 1/n

Step-by-step explanation:

Here, we want to make t the subject of the formula

we start by equating both sides so as to remove the root

we have this as;

m(t + n)/t = p^2

m(t + n) = tp^2

mt + mn = tp^2

mn = tp^2 - mt

mn = t(p^2-m)

t = (p^2 - m)/mn

t = p^2/mn - 1/n

6 0

2 years ago

What is this answer???

wlad13 [49]

Answer:

∠ ABC = 116°

Step-by-step explanation:

Since the angles are supplementary, they sum to 180° , that is

8x - 36 + 4x - 12 = 180

12x - 48 = 180 ( add 48 to both sides )

12x = 228 ( divide both sides by 12 )

x = 19

Then

∠ ABC = 8x - 36 = 8(19) - 36 = 152 - 36 = 116°

5 0

2 years ago

1. Approximate the given quantity using a Taylor polynomial with n3.

Jet001 [13]

Answer:

See the explanation for the answer.

Step-by-step explanation:

Given function:

$f(x) = x^{1/4}$

The n-th order Taylor polynomial for function f with its center at a is:

$p_{n}(x) = f(a) + f'(a) (x-a)+\frac{f''(a)}{2!} (x-a)^{2} +...+\frac{f^{(n)}a}{n!} (x-a)^{n}$

As n = 3 So,

$p_{3}(x) = f(a) + f'(a) (x-a)+\frac{f''(a)}{2!} (x-a)^{2} +...+\frac{f^{(3)}a}{3!} (x-a)^{3}$

$p_{3}(x) = f(a) + f'(a) (x-a)+\frac{f''(a)}{2!} (x-a)^{2} +...+\frac{f^{(3)}a}{6} (x-a)^{3}$

$p_{3}(x) = a^{1/4} + \frac{1}{4a^{ 3/4} } (x-a)+ (\frac{1}{2})(-\frac{3}{16a^{7/4} } ) (x-a)^{2} + (\frac{1}{6})(\frac{21}{64a^{11/4} } ) (x-a)^{3}$

$p_{3}(x) = 81^{1/4} + \frac{1}{4(81)^{ 3/4} } (x-81)+ (\frac{1}{2})(-\frac{3}{16(81)^{7/4} } ) (x-81)^{2} + (\frac{1}{6})(\frac{21}{64(81)^{11/4} } ) (x-81)^{3}$

$p_{3} (x)$ = 3 + 0.0092592593 (x - 81) + 1/2 ( - 0.000085733882) (x - 81)² + 1/6

(0.0000018522752) (x-81)³

$p_{3} (x)$ = 0.0092592593 x - 0.000042866941 (x - 81)² + 0.00000030871254

(x-81)³ + 2.25

Hence approximation at given quantity i.e.

x = 94

Putting x = 94

$p_{3} (94)$ = 0.0092592593 (94) - 0.000042866941 (94 - 81)² +

0.00000030871254 (94-81)³ + 2.25

= 0.87037 03742 - 0.000042866941 (13)² + 0.00000030871254(13)³ +

2.25

= 0.87037 03742 - 0.000042866941 (169) +

0.00000030871254(2197) + 2.25

= 0.87037 03742 - 0.007244513029 + 0.0006782414503 + 2.25

$p_{3} (94)$ = 3.113804102621

Compute the absolute error in the approximation assuming the exact value is given by a calculator.

Compute $\sqrt[4]{94}$ as $94^{1/4}$ using calculator

Exact value:

$E_{a}$ (94) = 3.113737258478

Compute absolute error:

Err = | 3.113804102621 - 3.113737258478 |

Err (94) = 0.000066844143

If you round off the values then you get error as:

|3.11380 - 3.113737| = 0.000063

Err (94) = 0.000063

If you round off the values up to 4 decimal places then you get error as:

|3.1138 - 3.1137| = 0.0001

Err (94) = 0.0001

4 0

2 years ago

I need help!!! Question: Elena has a pet parakeet the weighs 6 when measured in one unit and 170 when measured in a different un

Arturiano [62]

6 is grams and the other is ounce.

A gram is smaller than an ounce

3 0

2 years ago

Read 2 more answers