Answer:
and as 
Step-by-step explanation:
Given
-- Missing from the question
Required
The behavior of the function around its vertical asymptote at 

Expand the numerator

Factorize

Factor out x + 1

We test the function using values close to -2 (one value will be less than -2 while the other will be greater than -2)
We are only interested in the sign of the result
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As x approaches -2 implies that:
Say x = -3


We have a negative value (-12); This will be called negative infinity
This implies that as x approaches -2, p(x) approaches negative infinity

Take note of the superscript of 2 (this implies that, we approach 2 from a value less than 2)
As x leaves -2 implies that: 
Say x = -2.1

We have a negative value (-56.1); This will be called negative infinity
This implies that as x leaves -2, p(x) approaches negative infinity

So, the behavior is:
and as 
Answer:
The answer is -2/3.
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Answer:
○ B) ⅘
Step-by-step explanation:
Starting from the second endpoint, you go four blocks <em>south</em><em> </em>over five blocks <em>west</em><em> </em>[<em>west</em><em> </em>and <em>south</em><em> </em>are negatives], giving you ⅘.
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It would be c because fe is a radius ba is a chord and ec isnt a line
If y varies directly as the square of x, that means that y=k*x^2. Plugging y=100 and x=5 into it, we get 100=k*5^2=k*25. Dividing by both sides, we get k=100/25=4. Going back to the original equation, we now know that y=4*x^2. Plugging 9=x in, we get 4*9^2=4*81=324=y