Note that
(4sqrt3)^2 = (2sqrt3)^2 + 6^2 [ 48 = 12 + 36] so the triangle is a right angled one with hypotenuse AB
So angle C = 90 degrees
sin A = 2 sqrt3 / 4 sqrt3 = 1.2 giving A = 30 degrees
and B = 90 - 30 = 60 degrees
A = 30, B = 60 and C = 90 degrees
The second one (9.5, 9 3/4, 9 3/8, 9.125)
Answer:
The value of 
.
Step-by-step explanation:
Diagram of the given scenario shown below.
Given that,
Distance from bench to Jasmyn is 
.
Distance from bench to Willard is 
.
From the Question,
The given wishing well is a circle and all the distance are tangent to the circle.
So, Triangle formed by these points are such as Δ
and Δ
.
Now, taking both Δ and Δ.
⇒ 
{Radius of circle are equal}
⇒ 
{Common side}
⇒ ∠
∠ {radius is always perpendicular
to the point of tangent }
∴ Δ ≅ Δ {By SAS congruence theorem}
Therefore, 
....(1) {corresponding part of
congruence triangle (CPCT)}
Thus,
⇒ 
{from equation (1)}
⇒ 
⇒
Hence, The value of .
Answer:
c₁ = 1/2 cos⁻¹ (2/π) = 0.44
c₂ = -1/2 cos⁻¹ (2/π) = -0.44
Step-by-step explanation:
the average value of f(x)=2 cos(2x) on ( − π/ 4 , π/ 4 ) is
av f(x) =∫[2*cos(2x)] dx /(∫dx) between limits of integration − π/ 4 and π/ 4
thus
av f(x) =∫[cos(2x)] dx /(∫dx) = [sin(2 * π/ 4 ) - sin(2 *(- π/ 4 )] /[ π/ 4 - (-π/ 4)]
= 2*sin (π/2) /(π/2) = 4/π
then the average value of f(x) is 4/π . Thus the values of c such that f(c)= av f(x) are
4/π = 2 cos(2c)
2/π = cos(2c)
c = 1/2 cos⁻¹ (2/π) = 0.44
c= 0.44
since the cosine function is symmetrical with respect to the y axis then also c= -0.44 satisfy the equation
thus
c₁ = 1/2 cos⁻¹ (2/π) = 0.44
c₂ = -1/2 cos⁻¹ (2/π) = -0.44
It is B 99.99% sure
hope its right :)
