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3 years ago

Hello! I need some help. Have a blessed day!

Mathematics

2 answers:

swat323 years ago

8 0

False ! have a blessed day as well.

kondor19780726 [428]3 years ago

7 0

Answer:

false is the correct answer of it if the answer going wrong sorry

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Working at home: According to the U.S Census Bureau, 41% of men who worked at home were college graduates. In a sample of 506 wo

sergejj [24]

Solution :

a). The point estimate of proportion of college graduates among women who work at home,

$\hat p =\frac{166}{506}$

= 0.3281

99.5% confidence interval

$=\left( \hat p \pm Z_{0.005/2} \sqrt{\frac{\hat p (1- \hat p)}{n}} \right)$

$=\left( 0.3281 \pm 2.81 \sqrt{\frac{0.3281 \times (1- 0.3281)}{506}} \right)$

$=(0.3281 \pm 0.0586)$

$=(0.2695, 0.3867)$

6 0

3 years ago

Find the slope of the line that passes through the two points below. (3,4) and (3,-1)

tangare [24]

Answer:

Slope = (-5,0)

Step-by-step explanation:

When given two points and asked to find the slope, you can find the answer using slope formula which is:

slope = (y2 - y1) / (x2-x1)

You have been given the points (3,4) and (3,-1). You can select which ones to be x1 and y1 and which ones to be x2 and y2. It doesn't matter which, so let's just do (3,4) are x1 and y1 and (3,-1) are x2 and y2. Now we can plug it into the formula.

Slope = (-1 - 4) / (3-3)

= -5 / 0

= -5,0

So the answer is (-5,0).

8 0

3 years ago

Read 2 more answers

The population of Preston is 89,000 and is decreasing by 1.8% each year. Write a formula that models the population as a functio

Fiesta28 [93]

Answer:

$P=89,000e^{-.018t}$

Step-by-step explanation:

I used this equation formula and just input the numbers given:

$P=P_{o}e^{rt}$

Where

P= final population

$P_{o}$ = original population

r = rate of growth

t = time

Hope this helps!

6 0

3 years ago

The heights of women in the USA are normally distributed with a mean of 64 inches and a standard deviation of 3 inches.

Rainbow [258]

Answer:

(a) 0.2061

(b) 0.2514

Step-by-step explanation:

Let X denote the heights of women in the USA.

It is provided that X follows a normal distribution with a mean of 64 inches and a standard deviation of 3 inches.

(a)

Compute the probability that the sample mean is greater than 63 inches as follows:

$P(\bar X>63)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{63-64}{3/\sqrt{6}})\\\\=P(Z>-0.82)\\\\=P(Z$

Thus, the probability that the sample mean is greater than 63 inches is 0.2061.

(b)

Compute the probability that a randomly selected woman is taller than 66 inches as follows:

$P(X>66)=P(\frac{X-\mu}{\sigma}>\frac{66-64}{3})\\\\=P(Z>0.67)\\\\=1-P(Z$

Thus, the probability that a randomly selected woman is taller than 66 inches is 0.2514.

(c)

Compute the probability that the mean height of a random sample of 100 women is greater than 66 inches as follows:

$P(\bar X>66)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{66-64}{3/\sqrt{100}})\\\\=P(Z>6.67)\\\\\ =0$

Thus, the probability that the mean height of a random sample of 100 women is greater than 66 inches is 0.

8 0

3 years ago

A mathematics teacher wanted to see the correlation between test scores and

SpyIntel [72]

Answer:

The homework grade, to the nearest integer, for a student with a test grade of 68 is 69.

Step-by-step explanation:

The general form of the linear regression equation is:

$y=a+bx$

Here,

y = dependent variable = test grade

x = independent variable = homework grade

a = intercept

b = slope

Compute the value of a and b as follows:

$a=\frac{\sum Y\cdot \sum X^{2}-\sum X\cdot\sum XY}{n\cdot \sum X^{2}-(\sum X)^{2}}\\\\=\frac{(592\times 44909)-(591\times45227)}{(8\times44909)-(591)^{2}}\\\\=-14.316$ $b=\frac{n\cdot \sum XY-\sum X\cdot\sum Y}{n\cdot \sum X^{2}-(\sum X)^{2}}\\\\=\frac{(8\times 45227)-(591\592)}{(8\times44909)-(591)^{2}}\\\\=1.195$

The linear regression equation that represents the set of data is:

$y=-14.316+1.195x$

Compute the value of x for y = 68 as follows:

$y=-14.316+1.195x$

$68=-14.316+1.195x\\1.195x=68+14.316\\1.195x=82.316\\x=68.884\\x\approx 69$

Thus, the homework grade, to the nearest integer, for a student with a test grade of 68 is 69.

8 0

3 years ago