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schepotkina [342]
3 years ago
14

Or a very large set of data the measured mean is found to be 288.6 with a standard deviation of 21.2. assuming the data to be no

rmally distributed, determine the range within which 75% of the data are expected to fall.
Mathematics
1 answer:
SashulF [63]3 years ago
8 0

The 68-95-99.7 rule tells us 68% of the probability is between -1 standard deviation and +1 standard deviation from the mean. So we expect 75% corresponds to slightly more than 1 standard deviation.

Usually the unit normal tables don't report the area between -σ and σ but instead a cumulative probability, the area between -∞ and σ. 75% corresponds to 37.5% in each half so a cumulative probability of 50%+37.5%=87.5%. We look that up in the normal table and get σ=1.15.

So we expect 75% of normally distributed data to fall within μ-1.15σ and μ+1.15σ

That's 288.6 - 1.15(21.2) to 288.6 + 1.15(21.2)

Answer: 264.22 to 312.98


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F(x) = 3x/x+7, what is the domain?
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.Given: F(x) = 3x2+ 1, G(x) = 2x - 3, H(x) = x
inna [77]

For this case we have the following functions:

F (x) = 3x ^ 2 +1\\G (x) = 2x-3\\H (x) = x

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G (x) * - 1 is given by:

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Thus, the correct option is the option is A.

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Thus, the correct option is the option is A.

We also have:

F (-2) = 3 (-2) ^ 2+ 1 = 3 (4)+ 1 = 12+ 1 = 13

Thus, the correct option is the option is B.

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ANswer:

Option A, A, B, C

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