9514 1404 393
Answer:
- Angle 1 = 139°
- Angle 2 = 41°
- x = 29; exterior angle = 131°
Step-by-step explanation:
These problems let you make use of the fact that the sum of the remote interior angles is equal to the exterior angle.
__
1. 53° +86° = ∠1
139° = ∠1
__
2. ∠2 +92° = 133°
∠2 = 133° -92°
∠2 = 41°
__
3. (x +9)° +93° = (4x+15)°
87 = 3x . . . . . . . . . . . . . . . . subtract x+15°
29 = x . . . . . . . divide by 3
The exterior angle is ...
(4x +15)° = (4·29 +15)° = 131° . . . exterior angle
Answer:
90 red pens
Step-by-step explanation:
we need to find the least common multiple of the numbers 3 , 5 , 6 , 9
6 = 2 × 3
9 = 3²
then
LCM(3,5,6,9) = 2×5×3² = 2×5×9 = 90
The number 90 can be divided into 3 ,5 ,6 ,9 with no remainder
Therefore the pack must have 90 pens or a multiple of 90
For example 180 , 270 ...
Answer:
????
Step-by-step explanation:
Where is the picture?
P.S. I am not answering this question JUST to get points, I will actually revise my answer correctly once you add in a picture! :)
Answer:
(a) 113.04m²
(b) 37.68m
Step-by-step explanation:
(a)
Area = πr²
=π(6)²
=36π
=113.04m²
(b)
Circumference = 2πr
2π(6) = 12π
=37.68m
If A varies directly with z, and A is 30 and z is 5, then when z is 1, A is 6.
z: 5 ÷ 5 = 1
A: 30 ÷ 5 = 6
Then, when z is 1, A is 6
So, when z is 9, A is...
z: 1 × 9 = 9
A: 6 × 9 = 54
A is 54
