3 years ago

Over which interval is the function f(x)=x^3-27/x^2-9 differentiable?

Mathematics

1 answer:

aksik [14]3 years ago

8 0

Answer:

Step-by-step explanation:

F(x)=x³-27/x²-9

F(x)=(-9)³-27/(-9)²-9

F(x)=-729-27/-81-9

F(x)=-756/-90

F(x)=42/5

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