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vagabundo [1.1K]

3 years ago

12

En una PA cuya razón es 16, el término que ocupa el lugar 4 es 61. Si el último término es 173, ¿cuántos términos tiene la progr

esión?

1 answer:

Dmitry_Shevchenko [17]3 years ago

3 0

Step-by-step explanation:

En una PA cuya razón es 16, el término que ocupa el lugar 4 es 61. Si el último término es 173, ¿cuántos términos tiene la progresión?

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Select all the statements that are true.

alexgriva [62]

Answer:

The product of 8x(5x−6) is 40x^2−48x

The product of (x−3)(5x−6) is 5x^2−21x+18

Step-by-step explanation:

<u><em>Verify each option</em></u>

Part 1) The product of 8x(5x−6) is 40x^2−48x

we have

$8x(5x-6)$

Applying distributive property

$8x(5x)-8x(6)\\40x^2-48x$

Compare with the given value

$40x^2-48x=40x^2-48x$

therefore

The statement is true

Part 2) The product of −4x(2x2+1) is −8x^3−5x

we have

$-4x(2x^{2}+1)$

Applying distributive property

$-4x(2x^{2})-4x(1)\\-8x^3-4x$

Compare with the given value

$-8x^3-4x \neq -8x^3-5x$

therefore

The statement is not true

Part 3) The product of (x−3)(5x−6) is 5x^2−21x+18

we have

$(x-3)(5x-6)$

Applying distributive property

$x(5x)-x(6)-3(5x)+3(6)\\5x^2-6x-15x+18\\5x^2-21x+18$

Compare with the given value

$5x^2-21x+18=5x^2-21x+18$

therefore

The statement is true

Part 4) The product of (2x+3)(x^2+3x−5) is 2x^3+9x^2+9x−25

we have

$(2x+3)(x^2+3x-5)$

Applying distributive property

$(2x)(x^2+3x-5)+(3)(x^2+3x-5)\\(2x^3+6x^2-10x)+(3x^2+9x-15)\\2x^3+9x^2-x-15$

Compare with the given value

$2x^3+9x^2-x-15 \neq 2x^3+9x^2+9x-25$

therefore

The statement is not true

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