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Black_prince [1.1K]
3 years ago
9

PLEASE HELP I WILL MARK YOU BRAINLIEST. FIND THE AREA

Mathematics
1 answer:
Mandarinka [93]3 years ago
7 0

Answer:

<em>The family will need to purchase 187 square ft carpeting.</em>

Step-by-step explanation:

<u>Area of Rectangles</u>

Given a rectangle with width W and length H, the area is calculated as follows:

A = W * H

The new carpet of the family has the shape provided in the figure. We have completed the shape to add some missing dimensions by adding and subtracting the given lengths. Please refer to the attached image.

The total area of the carpet is the sum of the areas of three rectangles.

The rectangle at the bottom has dimensions 3 ft x 20 ft, thus its area is:

A1 = 3 ft * 20 ft = 60 square ft

The rectangle at the middle has dimensions 3 ft x 17 ft, thus its area is:

A2 = 3 ft * 17 ft = 51 square ft

The rectangle at the top has dimensions 4 ft x 19 ft, thus its area is:

A3 = 4 ft * 19 ft = 76 square ft

The total area of the carpet is:

A = 60 square ft + 51 square ft + 76 square ft

A = 187 square ft

The family will need to purchase 187 square ft carpeting.

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The College Boards, which are administered each year to many thousands of high school students, are scored so as to yield a mean
Marysya12 [62]

Answer:

a) 15.87% of the scores are expected to be greater than 600.

b) 2.28% of the scores are expected to be greater than 700.

c) 30.85% of the scores are expected to be less than 450.

d) 53.28% of the scores are expected to be between 450 and 600.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 500, \sigma = 100

a. Greater than 600

This is 1 subtracted by the pvalue of Z when X = 600. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{600 - 500}{100}

Z = 1

Z = 1 has a pvalue of 0.8413.

1 - 0.8413 = 0.1587

15.87% of the scores are expected to be greater than 600.

b. Greater than 700

This is 1 subtracted by the pvalue of Z when X = 700. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{700 - 500}{100}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

2.28% of the scores are expected to be greater than 700.

c. Less than 450

Pvalue of Z when X = 450. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{450 - 500}{100}

Z = -0.5

Z = -0.5 has a pvalue of 0.3085.

30.85% of the scores are expected to be less than 450.

d. Between 450 and 600

pvalue of Z when X = 600 subtracted by the pvalue of Z when X = 450. So

X = 600

Z = \frac{X - \mu}{\sigma}

Z = \frac{600 - 500}{100}

Z = 1

Z = 1 has a pvalue of 0.8413.

X = 450

Z = \frac{X - \mu}{\sigma}

Z = \frac{450 - 500}{100}

Z = -0.5

Z = -0.5 has a pvalue of 0.3085.

0.8413 - 0.3085 = 0.5328

53.28% of the scores are expected to be between 450 and 600.

6 0
3 years ago
What is the solution to the equation below? 4x = ⅔
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Step-by-step explanation:

we divide both sides by 4 to single out the X

(4X) / 4 = (2/3)/4

simplify

X = 2/12

4 0
3 years ago
The height of a stack of DVD cases is proportional to the number of cases in the stack. The height of 6 DVD cases is 114 mm.
Zanzabum
OK so my answer is from what you’ve just explained that means you multiply the six and the 114 is 684 so that means if you have to do that to 13 of them that means 684×13 is what your equation would be in the answer to 684×13 is 8892
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2 years ago
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Eva8 [605]

Answer:

126 groups

Step-by-step explanation:

we know that

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The formula for the number of possible combinations of r objects from a set of n objects is given by

^nC_r=\frac{ {n!}}{r!(n-r)!}

In this problem we have

n=9, r=5

substitute

^9C_5=\frac{ {9!}}{5!(9-5)!}

^9C_5=\frac{ {9!}}{5!(4)!}

^9C_5=\frac{ {(9)(8)(7)(6)5!}}{5!(4)!}

^9C_5=\frac{ {9)(8)(7)(6)}}{(4*3*2*1)}

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Answer:

66

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