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gogolik [260]
3 years ago
10

Solve 17x - 2 = 7x + 8

Mathematics
2 answers:
romanna [79]3 years ago
6 0
<span>17x-2=7x+8

We simplify the equation to the form, which is simple to understand
<span>17x-2=7x+8

We move all terms containing x to the left and all other terms to the right.
<span>+17x-7x=+8+2

We simplify left and right side of the equation.
<span>+10x=+10

We divide both sides of the equation by 10 to get x.
<span>x=1</span></span></span></span></span>
Contact [7]3 years ago
5 0
<span>Solve 17x - 2 = 7x + 8
Subtract 7x to both sides
17x - 2 - 7x = 7x +8 -7x
Simplify
10x-2=8
Now, add 2 to both sides
10x - 2 +2 = 8 +2
Simplify
10x = 10
x = 10/10
x = 1

</span>
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More math help, please
malfutka [58]

Answer:

15) Quadratic Function : The 3x is squared

16) Linear Function : It is a straight line

17) Quadratic Function : The line is a U shape

18) Linear Function : There is one y value for every x value, and the points form a straight line

Step-by-step explanation:

Done

5 0
3 years ago
Assume that the helium porosity (in percentage) of coal samples taken from any particular seam is normally distributed with true
Feliz [49]

Answer:

a) The 95% CI for the true average porosity is (4.51, 5.19).

b) The 98% CI for true average porosity is (4.11, 5.01)

c) A sample size of 15 is needed.

d) A sample size of 101 is needed.

Step-by-step explanation:

a. Compute a 95% CI for the true average porosity of a certain seam if the average porosity for 20 specimens from the seam was 4.85.

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.96*\frac{0.78}{\sqrt{20}} = 0.34

The lower end of the interval is the sample mean subtracted by M. So it is 4.85 - 0.34 = 4.51

The upper end of the interval is the sample mean added to M. So it is 4.35 + 0.34 = 5.19

The 95% CI for the true average porosity is (4.51, 5.19).

b. Compute a 98% CI for true average porosity of another seam based on 16 specimens with a sample average of 4.56.

Following the same logic as a.

98% C.I., so z = 2.327

M = 2.327*\frac{0.78}{\sqrt{16}} = 0.45

4.56 - 0.45 = 4.11

4.56 + 0.45 = 5.01

The 98% CI for true average porosity is (4.11, 5.01)

c. How large a sample size is necessary if the width of the 95% interval is to be 0.40?

A sample size of n is needed.

n is found when M = 0.4.

95% C.I., so Z = 1.96.

M = z*\frac{\sigma}{\sqrt{n}}

0.4 = 1.96*\frac{0.78}{\sqrt{n}}

0.4\sqrt{n} = 1.96*0.78

\sqrt{n} = \frac{1.96*0.78}{0.4}

(\sqrt{n})^{2} = (\frac{1.96*0.78}{0.4})^{2}

n = 14.6

Rounding up

A sample size of 15 is needed.

d. What sample size is necessary to estimate the true average porosity to within 0.2 with 99% confidence?

99% C.I., so z = 2.575

n when M = 0.2.

M = z*\frac{\sigma}{\sqrt{n}}

0.2 = 2.575*\frac{0.78}{\sqrt{n}}

0.2\sqrt{n} = 2.575*0.78

\sqrt{n} = \frac{2.575*0.78}{0.2}

(\sqrt{n})^{2} = (\frac{2.575*0.78}{0.2})^{2}

n = 100.85

Rounding up

A sample size of 101 is needed.

8 0
4 years ago
Which farmers had more cows than pigs? Mimi, Yosef, Jacob, Emiel, Jaylan, Harold Connie, Josie, Jackson, Jose' Emiel, Jackson, J
Sidana [21]

Answer:

Connie, Josie, Patrick, Mimi, Emma

I took the test, I hope this helps! Its okay, but I tried the answer above, and it wasn't correct

Step-by-step explanation:

5 0
3 years ago
Calculate greatest common divisor by step approach and reduce to lowest terms: 180/440
Fantom [35]

Answer:

the (GCF) greatest common factor is 20

Step-by-step explanation:

7 0
3 years ago
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Kyong buys 6 smallcans of wood stain. Each can contains 250 milliliters ml how many liters of stain did Kyong buy
Tresset [83]
1.5 Liters

You have to multiply 250 by six and then you must move the decimal place 3 places back because of the rule
4 0
3 years ago
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