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ki77a [65]
3 years ago
12

21) Answer the question using the information given. Special cube-shaped dice are manufactured having side lengths of in. The di

ce are stored in rectangular prism boxes. What is the greatest number of dice that will fill the box? 405 dice 1,755 dice 1,026 dice
Mathematics
1 answer:
Elenna [48]3 years ago
7 0

Answer: Hello your question is missing some details but I will provide a general solution based on the scope of the problem and you can plugin the missing value

answer = Volume of rectangular prism box / volume of cube

Step-by-step explanation:

To determine the number of Dice that will fit in the rectangular prism box

First : calculate the volume of the cube box ( dice )

volume of a Cube box : V = L^3       where L = side length  

next : calculate the volume of the rectangular prism box

volume of rectangular prism box = L * b * h

L= length , b = width , h = height

final step : Divide the volume of the rectangular prism box by the volume of the cube box ( dice )

= ( L * b * h ) / ( L^3 )

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I need help with this question. I need to find the perimeter of the hexagon RSTUVW.​
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Answer:

  47.71

Step-by-step explanation:

Two "special" triangles are involved.

ΔSWR is a 30°-60°-90° right triangle, so will have sides in the ratio 1 : √3 : 2.

ΔUVW is a 45°-45°-90° right triangle so will have sides in the ratio 1 : 1 : √2.

For ΔSWR, the side SW is given as 6, so the other sides are ...

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For ΔUVW, the side WU is given as 8, so the other sides are ...

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Then the perimeter of the figure is ...

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