Question

2/(x+2) + 1/(x-5) add the fractions

Answer 1

Answer:

i think,the lcm of x+2 and x-5 is x+2 and x-5 so multiply through by it

(x+2)(x-5)×2/x+2=(x+2)(x-5)×1/x-5

so is 2(x-5)=1(x+2)

then remove bracket by multiplying

2×x-2×5=1×x+1×2

2x-10=x+2

collect like terms

2x-x=10-2

x=8

Answer 2

The answer will be: 3x-8/(x+2)(x-5)