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zlopas [31]
4 years ago
8

jeffrey purchased and downloaded 12 songs on monday. He purchased 3 songs on tuesday. The cost to download each song is $2. Writ

e a numerical expression to represent this situation
Mathematics
1 answer:
STatiana [176]4 years ago
5 0

Answer:  2 × 12 + 2 × 3 or 2 × (12 + 3)

Step-by-step explanation:

Here, the cost of one song = $ 2

If the downloaded song on Monday was 12,

Then, the total money spend on Monday = 2 × 12

Similarly, If the downloaded song on Tuesday is 3,

Then, the total money spend on Tuesday= 2 × 3

Thus, the total cost of the songs on Monday and Tuesday = 2 × 12 + 2 × 3  Or  2 × ( 12 + 3)

Which is the required numerical expression.

By solving it we get = 2 × 15 = 30

Therefore, he spent $ 30 on Monday and Tuesday in downloading songs.

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We can make ratios equivalent to 18:4 by dividing and multiplying on it.
1. (18:4)/2=9:2
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3. (18:4)*3=54:12

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The hours of daylight,y, in Utica in days, x, from January 1, 2013 can be modeled by the equation y=3.06sin(0.017x-1.40) + 12.23
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The month of January has 31 days, so from January 1st to February 14th, there are 31 + 14 or 45 days, namely x = 45.

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4 0
3 years ago
a band of 45 ewoks crash-landed in the forest last night. this sounds like a small problem, but the population will grow at the
kogti [31]

Given Information:

Starting population = P₀ = 45

rate of growth = 22%

Required Information:

Population every five years from this year to the year 2050 = ?

Answer:

Year \: 2020 = P(0) = 45e^{0} = 45\\\\Year \: 2025 = P(5) = 45e^{0.22*5} = 135\\\\Year \: 2030 = P(10) = 45e^{0.22*10} = 406\\\\Year \: 2035 = P(15) = 45e^{0.22*15} = 1,220\\\\Year \: 2040 = P(20) = 45e^{0.22*20} = 3,665\\\\Year \: 2045 = P(25) = 45e^{0.22*25} = 11,011\\\\Year \: 2050 = P(30) = 45e^{0.22*30} = 33,079\\\\

Step-by-step explanation:

The population growth can be modeled as an exponential function,

P(t) = P_0e^{rt}

Where P₀ is the starting population, r is the rate of growth of the population and t is the time in years.

We are given that starting population of 45 and growth rate of 22%

P(t) = 45e^{0.22t}

Assuming that the starting year is 2020,

Year \: 2020 = P(0) = 45e^{0} = 45\\\\Year \: 2025 = P(5) = 45e^{0.22*5} = 135\\\\Year \: 2030 = P(10) = 45e^{0.22*10} = 406\\\\Year \: 2035 = P(15) = 45e^{0.22*15} = 1,220\\\\Year \: 2040 = P(20) = 45e^{0.22*20} = 3,665\\\\Year \: 2045 = P(25) = 45e^{0.22*25} = 11,011\\\\Year \: 2050 = P(30) = 45e^{0.22*30} = 33,079\\\\

Therefore, the starting population of ewoks was 45 in 2020 and increased to 33,079 by 2050 in a time span of 30 years.

8 0
3 years ago
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