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Art [367]
3 years ago
6

Evaluate this expression for x=-5 and y=-5​

Mathematics
1 answer:
Talja [164]3 years ago
3 0

Answer:

x - 2y=5

Step-by-step explanation:

Given

x = -5; y=-5

x - 2y --- missing from question

Required

Evaluate

We have:

x - 2y

Substitute for x and y

x - 2y=-5 - 2*-5

x - 2y=-5 +10

x - 2y=5

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Calculate the number of acres required to produce 1,000 gallons of oil in one year from microalgae and soybeans. Which one (micr
Inessa05 [86]

Answer:

microalgae required less space.

Step-by-step explanation:

Amount of oil to be produced = 1,000 gallons

Now,

We know

10,000 gallons of oil is extracted from the miroalgae per acre per year

and,

From soyabeans the oil extracted = 50 gallons per acre per year

therefore,

To produce 1,000 gallons number of acres required by microalgae

= [ Amount of oil to be produced ] ÷ [ oil extracted per acre from microalgae]

= 1,000 ÷ 10,000

= 0.1 acres

similarly

To produce 1,000 gallons number of acres required by soyabeans

= [ Amount of oil to be produced ] ÷ [ oil extracted per acre from soyabeans]

= 1,000 ÷ 50

= 20 acres

hence,

microalgae required less space.

7 0
3 years ago
Can you show that this quadrilateral is a parallelogram?
larisa [96]
The diagonals intersect perpendicularly, two consecutive angled are supplementary, and that opposite angles are equal
5 0
3 years ago
Hey guys<br>im new here<br>please solve this for me with steps!<br>ill mark as the best answer​
Vinil7 [7]

Answer:

The factors of  2(x+y)^2-9(x+y)-5 is ((x+y)-5)(2x+2y+1)

Step-by-step explanation:

Given polynomial

=>2(x+y)^2-9(x+y)-5

To Find:

The factors of the polynomial =?

Solution:

Lets assume  k = (x+y)

Then 2(x+y)^2-9(x+y)-5 can be written as 2k^2-9k-5

Now by using quadratic formula

k =\frac{-b\pm\sqrt{(b^2-4ac}}{2a}

where

a= 2

b= -9

c= -5

Substituting the values, we get

k =\frac{-b\pm\sqrt{(b^2-4ac)}}{2a}

k =\frac{-(-9) \pm \sqrt{((-9)^2-4(2)(-5)}}{2(2))}

k =\frac{-(-9) \pm \sqrt{(81+40)}}{4}

k =\frac{-(-9) \pm \sqrt{(121)}}{4}

k =\frac{-(-9) \pm 11}}{4}

k= \frac{ 9 \pm 11}{4}

k =  \frac{20}{4}                         k =  \frac{-2}{4}    

k_1 =5                                      k_2 = -\frac{1}{2}

2k^2-9k-5= 2(k-5)(k+\frac{1}{2})

Solving the RHS we get

\frac{2}{2}(k-5)(2k+1)

(k-5)(2k+1)

Substituting k = x+y

((x+y)-5)(2(x+y+1)

((x+y)-5)(2x+2y+1)

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What is up !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
timofeeve [1]

Answer: the sky and planets

Step-by-step explanation:

the are above us

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2 years ago
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