Let A, B, and W denote the sets of students apply to Addis Ababa Uni (A), Bahir Dar Uni (B), or Wachemo Uni (W). Let U denote the universal set of all students in the class.
We're given the cardinalities of several sets:
• total number of students:
• A applicants:
• B applicants:
• W applicants:
• A and B applicants:
• A and W applicants:
• B and W applicants:
• non-applicants:
The last cardinality tells us students applied anywhere at all.
We want to find , the number of students that applied to each of the three universities.
By the inclusion/exclusion principle,
That is, we count up all the students in the sets A, B, and W, then subtract the number of students in each pairwise intersection to not double-count, then add back the number of students in the intersection of all three sets since it was removed in the previous step.
Now solve.
Answer:
<em>25metres</em>
Step-by-step explanation:
Complete question
<em>Shenelle has 100 meters of fencing to build a rectangular garden. The garden's area (in square meters) as a function of the garden's width xxx (in meters) is modeled by: A(x )= -(x-25)² + 625</em>
What width will produce the maximum garden area?
At maximum area of the garden dA/dx = 0
dA/dx = -2(x-25)
0 =-2(x-25)
-2(x-25) = 0
x - 25 =0
x = 0+25
x = 25
<em>Hence the width that will produce the maximum garden area is 25metres</em>
Answer:
the next number in the sequence would be 7.68
Step-by-step explanation:
you are multiplying by 4. 0.03 multiplied by 4 equals 0.12, and so on.
Answer:
Step-by-step explanation:
Use the following formulas:
surface area of rectangular prism: A = 2wl + 2lh + 2hw
volume of rectangular prism: lwh
surface area of cylinder: A=2πrh+2πr^2
volume of cylinder: V=πr^2h
using these formulas, the surface area of the box is 424.3
the volume of the box is about 511.3
the surface area of the cylinder is about 275.77
the volume is 342.12
knowing this, the cylinder uses less material but the box holds more soup.
<span>24.
The number of results is simply the product of the number of possibilities for each object tossed. Each coin may lands heads up, or tails up, for 2 possibilities each. And the die may land with 6 possible faces up. So the number of possibilities is 2 * 2 * 6 = 24.
So the total number of possible results is 24.</span>