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3 years ago

What is the answer of this problem -7/3(3x-2)=-21 ?

Mathematics

1 answer:

weeeeeb [17]3 years ago

3 0

Answer:

= 11/3

Step-by-step explanation:

1. COMBINE MULTIPLIED TERMS INTO A SINGLE FRACTION

- 7/3 (3x-2)= -21

-7 (3x-2) = -21

-----------------------

2. DISTRIBUTE

-7( 3x- 2) ➗ 3 =-21

3. MULTIPLY ALL TERMS BY THE SAME VALUE TO ELIMINATE FRACTION DENOMINATORS

-21x + 14 ➗ 3 = 3 (-21)

4. CANCEL MULTIPLIED TERMS THAT ARE IN THE DENOMINATOR

3 ( -21x + 14) ➗ 3 (-21)

5. MULIPLY THE NUMBERS

-21x + 14 = 3(-21)

6. SUBTRACT 14 FROM BOTH SIDES OF THE EQUATION

-21x + 14 = -63

7. SIMPLIFY

-21x = - 77

8. DIVIDE BOTH SIDES OF THE EQUATION BY THE SAME TERM

-21x/-21 = -77/-21

9. SIMPLIFY

x = 11/3

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Choose the correct simplification of x to the 12th power times z to the 11th power all over x to the 2nd power times z to the 4t

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Answer:

<h3>The option A) $x^{10}z^7$ is correct answer.</h3><h3>The correct simplification for the given expression $\frac{x^{12}\times z^{11}}{x^2\times z^4}$ is $x^{10}z^7$ </h3>

Step-by-step explanation:

Given expression is x to the 12th power times z to the 11th power all over x to the 2nd power times z to the 4th power.

The given expression can be written as $\frac{x^{12}\times z^{11}}{x^2\times z^4}$

<h3>To choose the correct simplification of the given expression :</h3>

Now we have to simplify the given expression as below

$\frac{x^{12}\times z^{11}}{x^2\times z^4}$

$=x^{12}\times z^{11}(x^{-2}\times z^{-4})$ ( by using the identity $\frac{1}{a^m}=a^{-m}$ )

$=(x^{12}.x^{-2})\times (z^{11}.z^{-4})$

$=x^{12-2}\times z^{11-4}$ ( by using the identity $a^m.a^n=a^{m+n}$ )

$=x^{10}\times z^7$

$=x^{10}z^7$

∴ $\frac{x^{12}\times z^{11}}{x^2\times z^4}=x^{10}z^7$

<h3>The correct simplification for the given expression $\frac{x^{12}\times z^{11}}{x^2\times z^4}$ is $x^{10}z^7$ </h3><h3>Hence option A) $x^{10}z^7$ is correct answer.</h3>

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