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Arisa [49]
2 years ago
9

What fraction of a pound is eighty pence

Mathematics
2 answers:
AnnZ [28]2 years ago
8 0
4/5 is the the fraction of a pound is eighty pence
horsena [70]2 years ago
8 0
4/5 is the fraction of 80%
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Josh works h hours in a week. To find his weekly pay he multiplies his hours by his pay of $30 per hour and adds $5 for his sale
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3 years ago
Determine the value of s, the arc length (measured in inches) cut off in a circle with a radius of 3.4 inches by an angle with a
AleksandrR [38]

Answer:

Arc length s = 15.3 inches

Step-by-step explanation:

We know that length of an arc that subtends an angle θ radians at the center is given by

s=r\times \Theta

where

r is the radius of the circle

θ  is the angle subtended in radians

Thus applying values we get s=3.4\times \ 4.5radians

thus s = 15.3 inches

4 0
3 years ago
Audrey, an astronomer is searching for extra-solar planets using the technique of relativistic lensing. Though there are believe
Stolb23 [73]

Answer:

Step-by-step explanation:

The model N (t), the number of planets found up to time t, as a Poisson process. So, the N (t) has distribution of Poison distribution with parameter (\lambda t)

a)

The mean for a month is, \lambda = \frac{1}{3} per month

E[N(t)]= \lambda t\\\\=\frac{1}{3}(24)\\\\=8

(Here. t = 24)

For Poisson process mean and variance are same,

Var[N (t)]= Var[N(24)]\\= E [N (24)]\\=8

 

(Poisson distribution mean and variance equal)

 

The standard deviation of the number of planets is,

\sigma( 24 )] =\sqrt{Var[ N(24)]}=\sqrt{8}= 2.828

b)

For the Poisson process the intervals between events(finding a new planet) have  independent  exponential  distribution with parameter \lambda. The  sum  of K of these  independent exponential has distribution Gamma (K, \lambda).

From the given information, k = 6 and \lambda =\frac{1}{3}

Calculate the expected value.

E(x)=\frac{\alpha}{\beta}\\\\=\frac{K}{\lambda}\\\\=\frac{6}{\frac{1}{3}}\\\\=18

(Here, \alpha =k and \beta=\lambda)                                                                      

C)

Calculate the probability that she will become eligible for the prize within one year.

Here, 1 year is equal to 12 months.

P(X ≤ 12) = (1/Г  (k)λ^k)(x)^(k-1).(e)^(-x/λ)

=\frac{1}{Г  (6)(\frac{1}{3})^6}(12)^{6-1}e^{-36}\\\\=0.2148696\\=0.2419\\=21.49%

Hence, the required probability is 0.2149 or 21.49%

5 0
3 years ago
Please help with question 22b! Thanks :)
NNADVOKAT [17]
6.5 liters per 100 km travelled. 30% of 5 is 1.5, so adding this to the original amount results in 6.5
8 0
2 years ago
Read 2 more answers
A gym membership is $25 a month plus $15 fee. How many months/weeks can $200 cover?
Eddi Din [679]
The Equation: 25 + 15= 40. 40 x 5 = 200

The answer is 5 months

I am pretty positive this is correct. Sorry if I am wrong. Good luck!
5 0
2 years ago
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